解题思路:给出两个数列an,bn,其中an,bn中元素的顺序可以任意改变,求an,bn的LCS 因为数列中的元素可以按任意顺序排列,所以只需要求出an,bn中的元素有多少个是相同的即可. 反思:一开始以为就是求LCS,一直WA,后来才发现可以按任意顺序排列元素,把相同的元素都排在一起,就是最长的子序列. Puzzle Time Limit: 2 Seconds      Memory Limit: 65536 KB For sequences of integers a and b, if yo…

大模拟:枚举6个方向.检查每一个0是否能移动 Puzzle Time Limit: 2 Seconds      Memory Limit: 65536 KB Little Georgie likes puzzles very much. Recently he has found a wooden triangle in the box with old toys. The side of the triangle is n inches long. The triangle is divid…

题意:n个数字的串,每取出一个数字的代价为该数字和左右的乘积(1.n不能取),问最小代价 思路:dp[i][j]表示把i~j取到只剩 i.j 的最小代价. 代码: #include<set> #include<map> #include<cmath> #include<queue> #include<cstdio> #include<cstring> #include<algorithm> typedef long lon…

ZOJ Problem Set - 3435 Ideal Puzzle Bobble Time Limit: 2 Seconds      Memory Limit: 65536 KB Have you ever played Puzzle Bobble, a very famous PC game? In this game, as a very cute bobble dragon, you must keep shooting powerful bubbles to crush all t…

Multiplication Puzzle ZOJ - 1602 传送门 The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one card out of the row and scores the number of points equal to the product of the…

ZOJ 3541 题目大意:有n个按钮,第i个按钮在按下ti 时间后回自动弹起,每个开关的位置是di,问什么策略按开关可以使所有的开关同时处于按下状态 Description There is one last gate between the hero and the dragon. But opening the gate isn't an easy task. There were n buttons list in a straight line in front of the gate…

Number Puzzle Time Limit: 2 Seconds      Memory Limit: 65536 KB Given a list of integers (A1, A2, ..., An), and a positive integer M, please find the number of positive integers that are not greater than M and dividable by any integer from the given…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3541 题意:有一排开关,有个开关有两个值t和d,t是按下开关后在t秒后会自动弹起,d为距离最左端点的距离.问是否能找到一个按开关的顺序使得在某一时刻所有开关都打开. 思路: 首先要找一个最优子结构性质. 对于区间[l,r]来说,我们可以从任意一点出发,现在如果我们从中间的一点出发,那么必然要先去一个端点,然后再去另一个端点,那么在这个过程中,有些开关可能会经过多次,比如从…

1.题目描写叙述:点击打开链接 2.解题思路:本题是一道隐式图的搜索题目.一般来说,这类题目首先要定义状态,接下来是弄清楚状态怎样转移,以及状态怎样判重,怎样推断当前状态是否和目标状态同样.至于求解最短路就是经常使用的BFS就可以. 接下来我们逐一展开讨论. 1.状态的定义:看到这道题,猛一下会想着把每一个字符分别用01表示,然后看成二进制码进行状态压缩,这个状态定义尽管能够,可是显然,状态过于精确和复杂,假设把一行给压缩成一个整数,那么一个完整的图案要用8*9.即72个数才干描写叙述.显然过于…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=4119 依然是三维空间内求(1,1,1)~(a,b,c)能看到的整点数,平移一下转化成(0,0,0)~(a-1,b-1,c-1)就和前一题就一样了 还是莫比乌斯反演求gcd(a,b,c)=1的组数,公式还是sigma{u(d) * ((a/d+1) * (b/d+1) * (c/d+1) - 1)} 但直接暴力会T...所以加了分块优化...因为当a/d,b/d,c/d的值保持…