485. Max Consecutive Ones【easy】】的更多相关文章

485. Max Consecutive Ones[easy] Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number…
Find the second max number in a given array. Notice You can assume the array contains at least two numbers.   Example Given [1, 3, 2, 4], return 3. Given [1, 2], return 1. 解法一: public class Solution { /** * @param nums: An integer array. * @return: T…
problem 485. Max Consecutive Ones solution1: class Solution { public: int findMaxConsecutiveOnes(vector<int>& nums) { ; , max = INT_MIN; ; i<nums.size(); i++) { ) ans++; ) { if(max<ans) max = ans; ans = ; } } return max>ans ? max : ans;…
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561. Array Partition I[easy] Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Inpu…
217. Contains Duplicate[easy] Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 解法一: clas…
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