/** 题目:hdu3667 Transportation 拆边法+最小费用最大流 链接:http://acm.hdu.edu.cn/showproblem.php?pid=3667 题意:n个城市由m条有向边连接.要从城市1运输k流量到城市n.每条边有可以运输的流量容量,以及费用系数ai. 费用系数指该条边的费用为该条边的运输流量x的平方乘以ai.即ai*x^2. 如果无法运输k流量,输出-1,否则输出从城市1运输k流量到城市n的最小花费. 思路:拆边法+最小费用最大流 假设从u->v 容量为…

题目链接:https://vjudge.net/problem/HDU-3667 Transportation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3083    Accepted Submission(s): 1341 Problem Description There are N cities, and M directe…

Transportation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2464    Accepted Submission(s): 1052 Problem Description There are N cities, and M directed roads connecting them. Now you want to…