HDU 1025 LIS二分优化

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HDU 1025 LIS二分优化

题目链接: acm.hdu.edu.cn/showproblem.php?pid=1025 Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 28755 Accepted Submission(s): 8149 Problem Description…

HDU 1025 (LIS+二分) Constructing Roads In JGShining's Kingdom

这是最大上升子序列的变形,可并没有LIS那么简单. 需要用到二分查找来优化. 看了别人的代码,给人一种虽不明但觉厉的赶脚直接复制粘贴了,嘿嘿原文链接: http://blog.csdn.net/ice_crazy/article/details/7536332 假设存在一个序列d[1..9] = 2 1 5 3 6 4 8 9 7,可以看出来它的LIS长度为5.下面一步一步试着找出它.我们定义一个序列B,然后令 i = 1 to 9 逐个考察这个序列.此外,我们用一个变量Len来记录现在最长…

POJ 3903：Stock Exchange（裸LIS + 二分优化）

http://poj.org/problem?id=3903 Stock Exchange Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 5983 Accepted: 2096 Description The world financial crisis is quite a subject. Some people are more relaxed while others are quite anxious. J…

HDU 1025：Constructing Roads In JGShining's Kingdom（LIS+二分优化）

http://acm.hdu.edu.cn/showproblem.php?pid=1025 Constructing Roads In JGShining's Kingdom Problem Description JGShining's kingdom consists of 2n(n is no more than 500,000) small cities which are located in two parallel lines.Half of these cities are…

HDU 1025 DP + 二分

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1025 求最长递增子序列,O(n^2)的复杂度超时,需要优化为O(n*logn) f[i]存储长度为i的最小末尾 #include<stdio.h> int poor[500010], f[500010]; int main() { int n, k = 1; while (scanf("%d", &n) != EOF) { int m, m1; for (int i = 0…

hdu 1025 lis 注意细节！！！【dp】

感觉这道题浪费了我半个小时的生命......哇靠!原来输出里面当len=1时是road否则是roads!!! 其实做过hdu 1950就会发现这俩其实一样,就是求最长上升子序列.我用结构体记录要连线的两个city,对一个数组排序再求相应的另一个数组lis. 开始WA还以为我写错了, 造了数据测一下没错啊...又想是不是情况没考虑全,比如一个城市可以连好多城市,好多城市可以连一个城市???巴拉巴拉...后来发现只可以一对一啊....死在这种细节上真的是欲哭无泪.. #include<iostrea…