Sum Of Gcd(hdu 4676)】的更多相关文章

Sum Of Gcd Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 738    Accepted Submission(s): 333 Problem Description Given you a sequence of number a1, a2, ..., an, which is a permutation of 1...n…
Sum Of Gcd 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=4676 Description Given you a sequence of number a1, a2, ..., an, which is a permutation of 1...n. You need to answer some queries, each with the following format: Give you two numbers L, R, y…
任意门:http://acm.hdu.edu.cn/showproblem.php?pid=4676 Sum Of Gcd Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 908    Accepted Submission(s): 438 Problem Description Given you a sequence of numb…
Given you a sequence of number a 1, a 2, ..., a n, which is a permutation of 1...n. You need to answer some queries, each with the following format: Give you two numbers L, R, you should calculate sum of gcd(a[i], a[j]) for every L <= i < j <= R.…
The sum of gcd Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description You have an array A,the length of A is nLet f(l,r)=∑ri=l∑rj=igcd(ai,ai+1....aj)   Input There are multiple test cases. The first li…
题目链接:hdu 5381 The sum of gcd 将查询离线处理,依照r排序,然后从左向右处理每一个A[i],碰到查询时处理.用线段树维护.每一个节点表示从[l,i]中以l为起始的区间gcd总和.所以每次改动时须要处理[1,i-1]与i的gcd值.可是由于gcd值是递减的,成log级,对于每一个gcd值记录其区间就可以.然后用线段树段改动,可是是改动一个等差数列. #include <cstdio> #include <cstring> #include <vecto…
[题目] The sum of gcd Problem Description You have an array A,the length of A is nLet f(l,r)=∑ri=l∑rj=igcd(ai,ai+1....aj) Input There are multiple test cases. The first line of input contains an integer T, indicating the number of test cases. For each…
The sum of gcd Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 23    Accepted Submission(s): 4 Problem Description You have an array A,the length of A is n Let f(l,r)=∑ri=l∑rj=igcd(ai,ai+1....a…
The sum of gcd Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 641    Accepted Submission(s): 277 Problem Description  You have an array A with the length of $n$ \[Let\quad f(l,r) = \sum_{i = l}…
D - GCD HDU - 1695 思路: 都 除以 k 后转化为  1-b/k    1-d/k中找互质的对数,但是需要去重一下  (x,y)  (y,x) 这种情况. 这种情况出现 x  ,y 肯定 都在 min  (b/k, d/k)  ,所以 奇数 最后 减去 一半 即可. #include<bits/stdc++.h> using namespace std; #define ll long long #define maxn 1234567 bool vis[maxn+10];…