A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1,a2,···,an), the next n-tuple in the sequence is formed by taking the absolute differences of neighboring integers: (a1,a2,···,an) → (|a1 − a2|,|a2 − a3|,···,|a…

       Ducci Sequence Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu   Description A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, ... , an), the next n-tuple in the sequence is fo…

Ducci Sequence Description   A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, ... , an), the next n-tuple in the sequence is formed by taking the absolute differences of neighboring integers: ( a1, a2, ...…

A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, · · · , an), the next n-tuple in the sequence is formed by taking the absolute differences of neighboring integers: (a1, a2, · · · , an) → (|a1 − a2|, |a2 −…

题目: 1594 - Ducci Sequence Asia - Seoul - 2009/2010A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, ... , an), the next n-tuple in the sequence is formed by taking the absolute differences of neighboring in…

Description   A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, ... , an), the next n-tuple in the sequence is formed by taking the absolute differences of neighboring integers: ( a1, a2, ... , an)  (| a1 -…

书上具体所有题目:http://pan.baidu.com/s/1hssH0KO 代码:(Accepted,20 ms) //UVa1594 - Ducci Sequence #include<iostream> #include<algorithm> #include<cmath> #include<vector> using namespace std; int T,N; bool is_zero(vector<int> &d) {…

A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, ... , an), the next n-tuple in the sequence is formed by taking the absolute differences of neighboring integers: ( a1, a2, ... , an)  (| a1 - a2|,| a2 - a3…

水题,算出每次的结果,比较是否全0,循环1000次还不是全0则LOOP AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cctype> #include <cstring> #include <string> #include <sstream> #include <vector> #include <set…

题意: 对于一个n元组(a0,a1,...),一次变换后变成(|a0-a1|,|a1-a2|,...) 问1000次变换以内是否存在循环. 思路: 模拟,map判重 代码: #include <cstdio> #include <cstring> #include <map> #include <cmath> #include <algorithm> using namespace std; struct Node{ ]; int n; void…