Title: Sort a linked list in O(n log n) time using constant space complexity. 思路:考虑快速排序和归并排序,但是我的快速排序超时了 ListNode* sortList(ListNode* head) { if (!head) return NULL; int m_val = head->val; ListNode* left = NULL,*right = NULL; ListNode* p_left = NULL,…
Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Example:(1) Given nums = [1, 5, 1, 1, 6, 4], one possible answer is [1, 4, 1, 5, 1, 6]. (2) Given nums = [1, 3, 2, 2, 3, 1], one possible answer is [2, 3…
称号:Sort a linked list in O(n log n) time using constant space complexity. 对一个单链表进行排序,要求时间复杂度为O(n log n),空间复杂度为常量 分析:在排序中高速排序,堆排序,归并排序等都是能够在O(n log n)的时间复杂度之内完毕的. 的原地排序,但必须是在能够反向索引的情况下.比如通过下标的减法向前索引.或者通过双向指针进行索引(双向链表). b) 堆排序必需要大小为n的额外空间,不考虑. c) …
称号:Sort a linked list in O(n log n) time using constant space complexity. 思路:要求时间复杂度O(nlogn) 知识点:归并排序,链表找到中点的方法 存在的缺点:边界条件多考虑!.! /** * LeetCode Sort List Sort a linked list in O(n log n) time using constant space complexity. * 题目:将一个单链表进行排序,时间复杂度要求为o…
leetcode 148. Sort List 提交网址: https://leetcode.com/problems/sort-list/ Total Accepted: 68702 Total Submissions: 278100 Difficulty: Medium ACrate: 24.7% Sort a linked list in O(n log n) time using constant space complexity. 由于需要使用常量空间,即S(n)=O(1),故需要…
Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... Example 1: Input: nums = [1, 5, 1, 1, 6, 4] Output: One possible answer is [1, 4, 1, 5, 1, 6]. Example 2: Input: nums = [1, 3, 2, 2, 3, 1] Output: One po…
