LintCode 58: Compare Strings 题目描述 比较两个字符串A和B,确定A中是否包含B中所有的字符.字符串A和B中的字符都是大写字母. 样例 给出A = "ABCD" B = "ACD",返回true 给出A = "ABCD" B = "AABC", 返回false Fri Mar 17 2017 思路 这道题跟前面一道『两个字符串是变位词』很相似,不同的只是在这题中两个字符串的长度可以不相等. 可以用同…

problem 1170. Compare Strings by Frequency of the Smallest Character 参考 1. Leetcode_easy_1170. Compare Strings by Frequency of the Smallest Character; 完…

题目: 比较字符串 比较两个字符串A和B,确定A中是否包含B中所有的字符.字符串A和B中的字符都是 大写字母 样例 给出 A = "ABCD" B = "ACD",返回 true 给出 A = "ABCD" B = "AABC", 返回 false 注意 在 A 中出现的 B 字符串里的字符不需要连续或者有序. 解题: 用数组,或者用HashMap都可以,由于char String转换成Integer不是很熟悉,搞了好久...…

Compare two strings A and B, determine whether A contains all of the characters in B. The characters in string A and B are all Upper Case letters. Notice The characters of B in A are not necessary continuous or ordered. Example For A = "ABCD", B…

1. 把string变为char数组 2. 排序Arrays.sort() public class Solution { /** * @param s: The first string * @param b: The second string * @return true or false */ public boolean anagram(String s, String t) { if(s == null || t == null) return false; if(s.length(…

这是小川的第412次更新,第444篇原创 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第263题(顺位题号是1170).在一个非空字符串s上定义一个函数f(s),该函数计算s中最小字符的出现频率.例如,如果s ="dcce",则f(s)= 2,因为最小字符为"c",其频率为2. 现在,给定字符串数组queries和words,返回一个整数数组answer, 其中每个answer[i]是使得f(queries[i]) < f(W)的单词数量,其…

题目如下: Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c"and its frequency is 2. Now, giv…

Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c" and its frequency is 2. Now, given st…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双重循环 日期 题目地址:https://leetcode.com/problems/compare-strings-by-frequency-of-the-smallest-character/ 题目描述 Let's define a function f(s) over a non-empty string s, which calculates…

Yet Another Source Code for LintCode Current Status : 232AC / 289ALL in Language C++, Up to date (2016-02-10) For more problems and solutions, you can see my LintCode repository. I'll keep updating for full summary and better solutions. See cnblogs t…