uva 116 单向TSP】的更多相关文章

这题的状态很明显. 转移方程就是 d(i,j)=min(d(i+1,j+1),d(i,j+1),d(i-1,j+1)) //注意边界 我用了一个next数组方便打印结果,但是一直编译错误,原来是不能用next命名数组,会和std::next冲突. AC代码 #include<cstdio> #include<algorithm> using namespace std; const int maxn=100+5; const long long INF=(1<<30);…
https://cn.vjudge.net/problem/UVA-116 题意:给出m行n列的整数矩阵,从第一列任何一个位置出发每次往右,右上或右下走一格,最终到达最后一列,要求经过的整数之和最小. #include<iostream> #include<algorithm> using namespace std; const int INF = 0x7FFFFFFF; + ; int m, n; int a[maxn][maxn]; int dp[maxn][maxn]; i…
uva 116 Unidirectional TSP Background Problems that require minimum paths through some domain appear in many different areas of computer science. For example, one of the constraints in VLSI routing problems is minimizing wire length. The Traveling Sa…
主题: uva 116 Unidirectional TSP 意甲冠军:给定一个矩阵,当前格儿童值三个方向回格最小值和当前的和,就第一列的最小值并打印路径(同样则去字典序最小的). 分析:刚開始想错了,从前往后走,这种话没有办法控制字典序最小,用dfs标记了一下超时了. 事实上从后往前走就好了. 以后一定先想清楚顺序.然后dp的时候选择字典序最小的.用father数据记录就可以. AC代码: #include<iostream> #include<cstdio> #include&…
题意:给一个m行n列(m<=10, n<=100)的整数矩阵,从第一列任何一个位置出发每次往右,右上或右下走一格,最终到达最后一列.要求经过的整数之和最小.第一行的上一行是最后一行,最后一行的下一行是第一行.输出路径上每列的行号.多解时输出字典序最小的. 分析: 1.dp[i][j]---从第i行第j列到最后一列的最小开销. 2.列从右到左,从后一个状态可推知前一个状态的开销. #pragma comment(linker, "/STACK:102400000, 102400000&…
 Unidirectional TSP  Background Problems that require minimum paths through some domain appear in many different areas of computer science. For example, one of the constraints in VLSI routing problems is minimizing wire length. The Traveling Salesper…
Background Problems that require minimum paths through some domain appear in many different areas of computer science. For example, one of the constraints in VLSI routing problems is minimizing wire length. The Traveling Salesperson Problem (TSP) --…
Description    Unidirectional TSP  Background Problems that require minimum paths through some domain appear in many different areas of computer science. For example, one of the constraints in VLSI routing problems is minimizing wire length. The Trav…
简单动态规划题.用取模实现第一行与最后一行连续,注意取字典序即可. 我的解题代码如下: #include <iostream> #include <cstdio> #include <cstring> using namespace std; #define min(a,b) ((a<b)?a:b) #define max(a,b) ((a>b)?a:b) #define UL(i) ((i+M-1)%M) #define DL(i) ((i+1)%M) #…
题意:找最短路,知道三种行走方式,给出图,求出一条从左边到右边的最短路,且字典序最小. 用dp记忆化搜索的思想来考虑是思路很清晰的,但是困难在如何求出字典序最小的路. 因为左边到右边的字典序最小就必须从左边开始找,于是我们可以换个思路,dp时从右边走到左边,这样寻找路径就可以从左向右了. 代码: /* * Author: illuz <iilluzen[at]gmail.com> * Blog: http://blog.csdn.net/hcbbt * File: uva116.cpp * C…