1.题目描述 2.分析 利用递归实现. 3.代码 int findTilt(TreeNode* root) { if (root == NULL) ; ; nodesTilt(root,ans); return ans; } int nodesTilt(TreeNode *root, int & ans) { if (root == NULL) ; int tiltleft = nodesTilt(root->left, ans); int tiltright = nodesTilt(roo…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/binary-tree-tilt/#/description 题目描述 Given a binary tree, return the tilt of the whole tree. The tilt of a tree node is def…

Given the root of a binary tree, return the sum of every tree node's tilt. The tilt of a tree node is the absolute difference between the sum of all left subtree node values and all right subtree node values. If a node does not have a left child, the…

题目: Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 说明:1)下面有两种实现:递归(Recursive )与非递归(迭代iterati…

Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to the…

题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 说明: 1)二叉树可空 2)思路:a.根据前序遍历的特点, 知前序序列(PreSequence)的首个元素(PreSequence[0])为二叉树的根(root),  然后在中序序列(InSequence)中查找此根(…

这是悦乐书的第263次更新,第276篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第130题(顺位题号是563).给定二叉树,返回整棵树的倾斜度.树节点的倾斜被定义为所有左子树节点值的总和与所有右子树节点值的总和之间的绝对差. 空节点倾斜0.整棵树的倾斜度定义为所有节点倾斜的总和.例如: 输入: 1 / \ 2 3 输出:1 说明:节点2的倾斜度为0,节点3的倾斜度为0,节点1的倾斜:| 2-3 | = 1,二叉树的倾斜:0 + 0 + 1 = 1. 注意: 任何子…

1.题目描述 2.问题分析 使用层序遍历 3.代码 vector<int> v; vector<int> rightSideView(TreeNode* root) { if (root == NULL) return v; queue<TreeNode*> q; q.push(root); while (!q.empty()) { int size = q.size(); ; i < size; i++) { TreeNode *node = q.front()…

1.题目描述 2.问题分析 使用递归 3.代码 TreeNode* pruneTree(TreeNode* root) { if (root == NULL) return NULL; prun(root); return root; } void prun(TreeNode *root) { if (root == NULL) return; if (!has_ones(root->left)) root->left = NULL; if (!has_ones(root->right)…

1.题目描述 2.分析 找出最大元素,然后分割数组调用. 3.代码 TreeNode* constructMaximumBinaryTree(vector<int>& nums) { int size = nums.size(); ) return NULL; TreeNode *dummy = ); maxcont(dummy->left, , size-, nums); return dummy->left; } void maxcont(TreeNode* &…

1.题目描述 2.分析 使用递归. 3.代码 vector<string> ans; vector<string> binaryTreePaths(TreeNode* root) { if (root == NULL) return ans; leafPath(root,""); return ans; } void leafPath(TreeNode *root, string s) { if (root == NULL) return ; if (root-…

1.题目描述 2.题目分析 先遍历,再反转. 3.代码 vector<vector<int>> levelOrderBottom(TreeNode* root) { vector<vector<int>> ans; if (root == NULL) return ans; queue<TreeNode*> q; q.push(root); vector<int> v; while (!q.empty()) { int size =…

1.题目描述 2.问题分析 递归 3.代码 vector<int> postorderTraversal(TreeNode* root) { vector<int> v; postBorder(root,v); return v; } void postBorder(TreeNode *root, vector<int> &v) { if (root == NULL) return ; postBorder(root->left, v); postBord…

1.题目描述 2.问题分析 利用递归. 3.代码 vector<int> preorderTraversal(TreeNode* root) { vector<int> v; preBorder(root, v); return v; } void preBorder(TreeNode *root, vector<int> &v) { if (root == NULL) return ; v.push_back(root->val); preBorder(…

563. 二叉树的坡度 563. Binary Tree Tilt 题目描述 给定一个二叉树,计算整个树的坡度. 一个树的节点的坡度定义即为,该节点左子树的结点之和和右子树结点之和的差的绝对值.空结点的的坡度是 0. 整个树的坡度就是其所有节点的坡度之和. 每日一算法2019/6/10Day 38LeetCode563. Binary Tree Tilt 示例: 输入: 1 / \ 2 3 输出: 1 解释: 结点的坡度 2 : 0 结点的坡度 3 : 0 结点的坡度 1 : |2-3| = 1…

剑指offer 面试题39:判断平衡二叉树 提交网址:  http://www.nowcoder.com/practice/8b3b95850edb4115918ecebdf1b4d222?tpId=13&tqId=11192 时间限制:1秒       空间限制:32768K      参与人数:2481 题目描述 输入一棵二叉树,判断该二叉树是否是平衡二叉树. 分析: 平衡二叉树定义 递归解法 AC代码: #include<iostream> #include<vector&…

Problem Link: http://oj.leetcode.com/problems/binary-tree-postorder-traversal/ The post-order-traversal of a binary tree is a classic problem, the recursive way to solve it is really straightforward, the pseudo-code is as follows. RECURSIVE-POST-ORDE…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 来源: https://leetcode.com/problems/binary-tree-level-order-traversal-ii/ Given a binary tree, return the bottom-up level order traversal of its nodes' values.…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 来源: https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/ Given a binary tree, return the zigzag level order traversal of its nodes' values…

Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. For example, given preorder = [3,9,20,15,7] inorder = [9,3,15,20,7] Return the following binary tree: 3 / \ 9 20…

Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. For example, given inorder = [9,3,15,20,7] postorder = [9,15,7,20,3] Return the following binary tree: 3 / \ 9 2…

Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. For example, given inorder = [9,3,15,20,7] postorder = [9,15,7,20,3] Return the following binary tree: 3 / \ 9 2…

LeetCode--Diameter of Binary Tree Question Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass…

Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. For example, given inorder = [9,3,15,20,7] postorder = [9,15,7,20,3] Return the following binary tree: 3 / \ 9 2…

[LeetCode]199. Binary Tree Right Side View 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/binary-tree-right-side-view/description/ 题目描述: Given a binary tree, imagine yourself standing on the right side of it, return the values of the no…

原题链接在这里:https://leetcode.com/problems/binary-tree-tilt/description/ 题目: Given a binary tree, return the tilt of the whole tree. The tilt of a tree node is defined as the absolute difference between the sum of all left subtree node values and the sum…

Given a binary tree, return the tilt of the whole tree. The tilt of a tree node is defined as the absolute difference between the sum of all left subtree node values and the sum of all right subtree node values. Null node has tilt 0. The tilt of the …

Given a binary tree, return the tilt of the whole tree. The tilt of a tree node is defined as the absolute difference between the sum of all left subtree node values and the sum of all right subtree node values. Null node has tilt 0. The tilt of the …

Given a binary tree, return the tilt of the whole tree. The tilt of a tree node is defined as the absolute difference between the sum of all left subtree node values and the sum of all right subtree node values. Null node has tilt 0. The tilt of the …

Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys…