A - Investment Time Limit:1000MS Memory Limit:30000KB 64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2063 Description John never knew he had a grand-uncle, until he received the notary's letter. He learned that his late grand-uncle…
*注 虽然没什么人看我的博客但我还是要认认真真写给自己看 背包问题应用场景给定 n 种物品和一个背包.物品 i 的重量是 w i ,其价值为 v i ,背包的容量为C.应该如何选择装入背包中的物品,使得装入背包的总价值最大?*01 背包 *01 背包特点: 给定 n 种物品和一个背包 ( 每个物品只能选取一个).物品 i 的重量是w[i],其价值为v[i],背包的容量为C.应该如何选择装入背包中的物品,使得装入背包中的物品的总价值最大?*状态: dp[i][j] 表示在只能从 1-i 个物品中选…
POJ 2184 Cow Exhibition Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14657 Accepted: 5950 Description "Fat and docile, big and dumb, they look so stupid, they aren't much fun..." - Cows with Guns by Dana Lyons The cows want to…
Cow Exhibition Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 10200 Accepted: 3977 Description "Fat and docile, big and dumb, they look so stupid, they aren't much fun..." - Cows with Guns by Dana Lyons The cows want to prove to…
Proud Merchants Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 4257 Accepted Submission(s): 1757 Problem Description Recently, iSea went to an ancient country. For such a long time, it was…
所谓的全然背包,就是说物品没有限制数量的. 怎么起个这么intimidating(吓人)的名字? 事实上和一般01背包没多少差别,只是数量能够无穷大,那么就能够利用一个物品累加到总容量结尾就能够了. 本题要求装满的,故此添加个限制就能够了. #include <stdio.h> #include <stdlib.h> #include <string.h> inline int min(int a, int b) { return a < b? a : b; }…
题意:给出n种面值的硬币, 和这些硬币每一种的数量, 要求求出能组成的钱数(小于等于m) 思路:一开始直接用多重背包套上去超时了,然后就没辙了,然后参考网上的,说只需要判断是否能取到就行了,并不需要记录其价格,直接用bool判断是否能取到.就不会TLE了. 代码: #include<iostream> #include<cstdio> #include<cstring> using namespace std; int n,m; int v,sum; int a[200…
题意:多重背包模型 n种物品 每个m个 问背包容量下最多拿多少 这里要用二进制优化不然会超时 #include<iostream> #include<cstdio> #include<cstring> using namespace std; +; int dp[maxn]; ],c[]; int main(){ int n,m,maxnum; while(cin>>maxnum>>n){ int a,b; ; ;i<=n;i++){…
Balance Time Limit: 1000 MS Memory Limit: 30000 KB 64-bit integer IO format: %I64d , %I64u Java class name: Main [Submit] [Status] [Discuss] Description Gigel has a strange "balance" and he wants to poise it. Actually, the device is different fr…
题目链接:http://poj.org/problem?id=1837 Balance Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 10983 Accepted: 6824 Description Gigel has a strange "balance" and he wants to poise it. Actually, the device is different from any other…
poj3624 Charm Bracelet 模板题 没有要求填满,所以初始化为0就行 #include<cstdio> #include<iostream> using namespace std; #define N 15010 int n,m,v[N],c[N],f[N]; int main(){ scanf("%d%d",&n,&m); ;i<=n;i++) scanf("%d%d",&v[i],&…