Turn the corner Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1930    Accepted Submission(s): 736 Problem Description Mr. West bought a new car! So he is travelling around the city. One day h…

Problem Description Mr. West bought a new car! So he is travelling around the city.One day he comes to a vertical corner. The street he is currently in has a width x, the street he wants to turn to has a width y. The car has a length l and a width d.…

传送门 分析 根据这张图,我们只要使得h<=y即可,可以发现h是一个凸函数,故使用三分,具体见代码 代码 #include<cstdio> #include<cstring> #include<vector> #include<algorithm> using namespace std; const double eps = 1e-7; const double pi = acos(-1.0); #define ll long long #defin…

Turn the corner Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 151 Accepted Submission(s): 61   Problem Description Mr. West bought a new car! So he is travelling around the city. One day he come…

Turn the corner Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2229    Accepted Submission(s): 856 Problem Description Mr. West bought a new car! So he is travelling around the city. One day h…

Problem Description Mr. West bought a new car! So he is travelling around the city. One day he comes to a vertical corner. The street he is currently in has a width x, the street he wants to turn to has a width y. The car has a length l and a width d…

Turn the corner Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 654 Accepted Submission(s): 291   Problem Description Mr. West bought a new car! So he is travelling around the city. One day he com…

托一个学弟的福,学了一下他的最简便三分写法,然后找了一道三分的题验证了下,AC了一题,写法确实方便,还是我太弱了,漫漫AC路!各路大神,以后你们有啥好的简便写法可以在博客下方留个言或私信我,谢谢了! Turn the corner Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3196    Accepted Submission(s…

传送门 Turn the corner Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2081    Accepted Submission(s): 787 Problem Description Mr. West bought a new car! So he is travelling around the city. One da…

Problem Description Mr. West bought a new car! So he is travelling around the city. One day he comes to a vertical corner. The street he is currently in has a width x, the street he wants to turn to has a width y. The car has a length l and a width d…

这题是道三分的题,首先要分析满足条件的情况,这个就是平面几何的功夫了.要想车子能够转弯成功,最上面那个点到水平线的距离要小于等于y.这里h和s的公式就是利用平面几何的知识求出来的:s=l*cos(a)+w*sin(a)-x;s=l*cos(a)+w*sin(a)-x;其中s为最右边的那个点到拐角处的水平距离.因为角度和高度h满足凸函数的关系,因此想到利用角度采用三分的方法进行求解. #include"iostream" #include"stdio.h" #incl…

Turn the corner Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2785    Accepted Submission(s): 1102 Problem Description Mr. West bought a new car! So he is travelling around the city. One day h…

Turn the corner Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3070    Accepted Submission(s): 1232 Problem Description Mr. West bought a new car! So he is travelling around the city.One day he…

Turn the corner http://acm.hdu.edu.cn/showproblem.php?pid=2438 题目:一辆车能否在一个路口拐弯,看图就很明白啦. 算法:见下图,只要求出图中明黄色线段的最大值小于y就可以了.一图抵千言. #include <iostream> #include <cmath> using namespace std; double x,y,l,d; double f_angle(double angle) { return l*cos(…

                                                               B. The Meeting Place Cannot Be Changed The main road in Bytecity is a straight line from south to north. Conveniently, there are coordinates measured in meters from the southernmost build…

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2237    Accepted Submission(s): 859 Problem Description Mr. West bought a new car! So he is travelling around the city. One day he comes to a vert…

转载:https://www.linux.com/learn/linux-career-center/44184-the-kernel-newbie-corner-kernel-debugging-with-proc-qsequenceq-files-part-3 Finally, after two installments of the basics of debugging with sequence files, we're going to finish off by demonstr…

[方法] 字写大点,先注释框架 链表:指针走就行了,最多是两个同时一起走. 两个链表求交点 //corner case if (headA == null || headB == null) { return null; } //keep the same length int A_len = getLength(headA); int B_len = getLength(headB); while (A_len > B_len) { headA = headA.next; A_len--; }…

基于jquery的插件turn.js学习笔记 简介 turn.js是一个可以实现3d书籍展示效果的jq插件,使用html5和css3来执行效果.可以很好的适应于ios和安卓等触摸设备. How it works? 下面是官网展示的最简单的一个应用实例 1.编写html部分 <div id="flipbook"> <div class="hard"> Turn.js </div> <div class="hard&q…

Turn.js是一个内置的jQuery翻页插件1 html中引入<script type="text/javascript" src="js/turn.js"></script>2  创建html <div id="flipbook"> <div style="background-image:url(pages/01.jpg);"></div> <div st…

Text I was having dinner at a restaurant when Tony Steele came in. Tony worked in a layer's office years ago, but he is now working at a bank. He gets a good salary, but he always borrows money from his friends and never pays it back. Tony saw me and…

ural History Exam    二分 #include <iostream> #include <cstdlib> using namespace std; //二分查找 bool binarySearch(long a[], long x, int n){ ,right = n-; int middle; while (left <= right){ middle = (left+right)/; ; ; ; } ; } int cmp(const void *a…

webRTC支持点对点通讯,但是webRTC仍然需要服务端:  . 协调通讯过程中客户端之间需要交换元数据,    如一个客户端找到另一个客户端以及通知另一个客户端开始通讯.  . 需要处理NAT(网络地址转换)或防火墙,这是公网上通讯首要处理的问题.    所以我们需要了解服务端相关的知识:信令.Stun.trun.ice. 一.什么是信令 信令就是协调通讯的过程,为了建立一个webRTC的通讯过程,客户端需要交换如下信息:  . 会话控制信息,用来开始和结束通话,即开始视频.结束视频这些操作…

http://acm.hdu.edu.cn/showproblem.php?pid=5105 给定a,b,c,d,l,r,表示有一个函数f(x)=|a∗x3+b∗x2+c∗x+d|(L≤x≤R),求函数最大值. 考虑极点可能有0~2个.在极值点处函数的单调性会发生变化,所以最大值一定就在区间边界和极值点上.所以求下l,r,极值点的函数大小然后取最大的即可. #include <cstdio> #include <cstdlib> #include <cmath> #in…

原题:  Turn the pokers       思路:假设正面为0,反面为1.牌就像这样 000000....... .考虑到假如可以实现最终反面个数为m, 牌共n张, 则这n张排任取m个为反面其余都为正面的状况都能实现.于是转化为考虑最终可能出现1的个数的集合有哪些.       因为可能的个数集合是连续的(在最大最小值之内相差2的都可能), 所以每一次翻转之后的上下限都可以根据上一次所得的上下限推出.       最后算排列组合的适合需要用到组合数递推公式和费马小定理推论\( a^{p…

很好用的一款插件jQuery+turn.js翻书.文档和杂志3种特效演示 在线预览 下载地址 实例代码 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"…

when I upgrated my laptop's system to win8.*,I found it's hibernate when I clicked turn off button. but sometimes you need restart your computer.if you don't like this,you can change it.there is a new function which called turn on fast startup in win…

转自:http://blog.csdn.net/yu_xiang/article/details/9227023 在现实Internet网络环境中,大多数计算机主机都位于防火墙或NAT之后,只有少部分主机能够直接接入Internet.很多时候,我们希望网络中的两台主机能够直接进行通信,即所谓的P2P通信,而不需要其他公共服务器的中转.由于主机可能位于防火墙或NAT之后,在进行P2P通信之前,我们需要进行检测以确认它们之间能否进行P2P通信以及如何通信.这种技术通常称为NAT穿透(NAT Trav…

J. Right turn Time Limit: 1000ms Memory Limit: 65536KB frog is trapped in a maze. The maze is infinitely large and divided into grids. It also consists of n obstacles, where the i-th obstacle lies in grid (xi,yi). frog is initially in grid (0,0), hea…

今天用turn.js 做图书的翻页效果遇到问题: 图片路径总是出错 调了一天,总算调出来了 我用的thinkphp,其他的不知道是不是一样 三 个地方要改动: 1.后台查出地址 注意的地方:1.地址要完全的 2.js要用json格式的数据 $more = M('File')->where(array('id'=>$id))->find(); $more1 = json_decode($more['more'],true); foreach($more1 as $k => $v){…