题意 5702 Count The Repetitions 0x50「动态规划」例题 描述 定义 conn(s,n) 为 n 个字符串 s 首尾相接形成的字符串,例如: conn("abc",2)="abcabc" 称字符串 a 能由字符串 b 生成,当且仅当从字符串 b 中删除某些字符后可以得到字符串 a.例如"abdbec"可以生成"abc",但是"acbbe"不能生成"abc".…

http://contest-hunter.org:83/contest/0x50%E3%80%8C%E5%8A%A8%E6%80%81%E8%A7%84%E5%88%92%E3%80%8D%E4%BE%8B%E9%A2%98/5702%20Count%20The%20Repetitions 给两个串,第一个循环写$n1$次,求第二个最多可以循环写多少次使得其能与第一个循环串非连续匹配.$s \leqslant 100,n \leqslant 10^6$ 这个博客貌似鸽了许久了.. 可以想到朴素…

Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3]="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such tha…

Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…

Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…

Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…

https://leetcode.com/problems/count-the-repetitions/description/ 找循环节 https://www.cnblogs.com/grandyang/p/6149294.html…

Leetcode 466 直接给出DP方程 dp[i][k]=dp[i][k-1]+dp[(i+dp[i][k-1])%len1][k-1]; dp[i][k]表示从字符串s1的第i位开始匹配2^k个s2串需要的长度 最后通过一个循环 累积最多可以匹配多少个s2串 除以n2下取整就是答案 用倍增加速后 总的复杂度nlogn 而本题的n非常小 轻松AC 体会到倍增的魅力了吧. const int maxn=100+1,INF=1e+9; long long int dp[maxn][30]; cl…

Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…

题目链接 传送门 题意 定义一个特殊的串, 现在给出串S1和S2的参数, 问: S2最多可以多少个连接起来扔是S1的子序列, 求出这个最大值 解题思路 注意s1与S1的区别, 可以去看题目描述, 预处理出s1从s2的每一个字符开始匹配, s1可以匹配到s2串尾的数量, 即如果从s2的当前下标开始匹配, 这一个s1最多可以匹配多少s2, 这个s1匹配完成后匹配到了s2的哪一个字符, 下一个s1匹配s2的话应该从哪一个下标开始, 因为串长最长100, 这个预处理时间消耗是很少的, 有了这个预处理的结…