1112 Stucked Keyboard (20 分)   On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen…

1112 Stucked Keyboard(20 分) On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen, y…

此文章同步发布在我的CSDN上:https://blog.csdn.net/weixin_44385565/article/details/90041078   1112 Stucked Keyboard (20 分)   On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys wil…

1112 Stucked Keyboard (20 分) On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen,…

https://pintia.cn/problem-sets/994805342720868352/problems/994805357933608960 On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for …

题意:给定一个k,键盘里有些键盘卡住了,按一次会打出k次,要求找出可能的坏键,按发现的顺序输出,并且输出正确的字符串顺序. map<char,int>用来标记一个键是否为坏键,一开始的时候都为0,表明所有的键为坏键. 然后遍历每个字符,统计当前字符连续出现的次数cnt,则只要存在cnt%k!=0,则表明为好键,另其map=1. 最后再for一遍字符串,存储坏键字符串和正确字符串,最后输出即可. #include <iostream> #include <cstdio>…

找出一定没问题的字符(即一连串的额字符x个数能被k整除的),剩下的字符都是可能有问题的. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; int k;…

题意: 输入一个正整数K(1<K<=100),接着输入一行字符串由小写字母,数字和下划线组成.如果一个字符它每次出现必定连续出现K个,它可能是坏键,找到坏键按照它们出现的顺序输出(相同坏键仅输出一次,数据保证必定存在坏键),接着输出将坏键修好后原本的字符串(K个连续坏键只输出一次). trick: 测试点1答案错误原因:出现次数为K的倍数而不是大于等于K 测试点2,3错误原因:输出原字符串时没有检验最后一段连续相同字符是否为坏键(循环当中没有检验这一段) AAAAAccepted code:…

题目链接:https://pintia.cn/problem-sets/994805342720868352/problems/994805357933608960 这道题初次写的时候,思路也就是考虑从头到尾遍历一遍,然后如果一个字符重复出现k的倍数次的话,那么这个键就是坏的. 但是这样做交了一发是错的. 后来一想,如果 k = 3,然后出现了aaaba这样一个字符串,那我们并不能仅仅凭a出现了3次就认为a是一个坏键,因为如果它是坏键,那么每一次它在字符串中出现的时候出现的次数都会是k的倍数.…

On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen, you are supposed to list all…