HDU 1505 City Game(DP)】的更多相关文章

City Game Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4531    Accepted Submission(s): 1919 Problem Description Bob is a strategy game programming specialist. In his new city building game t…
F - City Game Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1505 Appoint description: Description Bob is a strategy game programming specialist. In his new city building game the gaming enviro…
1506意甲冠军:给你一个连续的直方图(拼贴底部长度1).求连续基质区. 对每一个直方图,分别向左向右进行扩展. #include<cstdio> #include<stdlib.h> #include<string.h> #include<string> #include<map> #include<cmath> #include<iostream> #include <queue> #include <…
http://acm.hdu.edu.cn/showproblem.php?pid=5791 Two Problem Description   Alice gets two sequences A and B. A easy problem comes. How many pair of sequence A' and sequence B' are same. For example, {1,2} and {1,2} are same. {1,2,4} and {1,4,2} are not…
Problem Description 小A想通过合理投资银行理财产品达到收益最大化.已知小A在未来一段时间中的收入情况,描述为两个长度为n的整数数组dates和earnings,表示在第dates[i]天小A收入earnings[i]元(0<=i<n).银行推出的理财产品均为周期和收益确定的,可描述为长度为m的三个整数数组start.finish和interest_rates, 若购买理财产品i(0<=i<m),需要在第start[i]天投入本金,在第finish[i]天可取回本…
Problem Description Bob is a strategy game programming specialist. In his new city building game the gaming environment is as follows: a city is built up by areas, in which there are streets, trees,factories and buildings. There is still some space i…
Best Financing Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 29    Accepted Submission(s): 3 Problem Description 小A想通过合理投资银行理财产品达到收益最大化.已知小A在未来一段时间中的收入情况,描述为两个长度为n的整数数组dates和earnings,表示在第dat…
点我看题目 题意 : 中文题不详述. 思路 : 根据题目描述及样例可以看出来,如果你第一个城市选的是生活费减花费大于等于0的时候才可以,最好是多余的,这样接下来的就算是花超了(一定限度内的花超),也可以通过前边的剩余来补充进去,就可以多玩一个.所以先存一下每个城市的生活费减去花费的剩余,然后从非负开始找,找一个数组存一下现在还剩下的多余花费,还要在找一个数组存一下当前点用的天数,可以从头开始重新选择新的城市. //HDU 1422 #include <stdio.h> #include <…
点我看题目 题意 : 中文题.在直线上接馅饼,能接的最多是多少. 思路 :这个题其实以前做过.....你将这个接馅饼看成一个矩阵,也不能说是一个矩阵,反正就是一个行列俱全的形状,然后秒当行,坐标当列,这也就是转化成了数字三角形问题,从下往上找最大路径.下边这个图正好是某位大神的,让我不厚道的截过来了....注意一下边界. 第0秒                       5                         (这里的数字指的是第N秒可能到达的位置坐标) 第1秒          …
Problem Description The signature of a permutation is a string that is computed as follows: for each pair of consecutive elements of the permutation, write down the letter 'I' (increasing) if the second element is greater than the first one, otherwis…