You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 递归 + 记忆化 动态规划 优化动态规划空间 日期 [LeetCode] 题目地址:https://leetcode.com/problems/house-robber/ Total Accepted: 67398 Total Submissions: 196356 Difficulty: Easy 题目描述 You are a profess…

你是一个专业的强盗,计划抢劫沿街的房屋.每间房都藏有一定的现金,阻止你抢劫他们的唯一的制约因素就是相邻的房屋有保安系统连接,如果两间相邻的房屋在同一晚上被闯入,它会自动联系警方.给定一个代表每个房屋的金额的非负整数列表,确定你可以在没有提醒警方的情况下抢劫的最高金额. 详见:https://leetcode.com/problems/house-robber/description/ Java实现: class Solution { public int rob(int[] nums) { in…

198. House Robber Total Accepted: 45873 Total Submissions: 142855 Difficulty: Easy You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing ea…

198. House Robber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected…

House Robber:不能相邻,求能获得的最大值 House Robber II:不能相邻且第一个和最后一个不能同时取,求能获得的最大值 House Robber III:二叉树下的不能相邻,求能获得的最大值 Paint House:用3种颜色,相邻的房屋不能用同一种颜色,求花费最小 Paint House II:用k种颜色,相邻的房屋不能用同一种颜色,求花费最小Paint Fence:用k种颜色,相邻的可以用同一种颜色,但不能超过连续的2个,求有多少种可能性 198. House Robb…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

题目描述: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will…

题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will a…

URL : https://leetcode.com/problems/house-robber/ You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent house…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

1 题目 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

要求 你是一个小偷,每个房子中有价值不同的宝物,但若偷连续的两栋房子,就会触发报警系统,求最多可偷价值多少的宝物 示例 [3,4,1,2],返回6[3,(4),1,(2)] [4,3,1,2],返回6[(4),3,1,(2)] 实现 暴力解法:检查所有房子的组合,对每个组合检查是否有相邻房子,若没有则记录其价值,找最大值((2^n)*n) 递归 记忆化搜索 1 class Solution { 2 private: 3 // memo[i] 表示抢劫nums[i...n)所能获得的最大收益 4…

House Robber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and…

题意是强盗能隔个马抢马,看如何获得的价值最高 动态规划题需要考虑状态,阶段,还有状态转移,这个可以参考<动态规划经典教程>,网上有的下的,里面有大量的经典题目讲解 dp[i]表示到第i匹马时的最大价值是多少, 因此所有的dp[i] = max(dp[i-2]+nums[i],dp[i-1]) (其中dp[0] = nums[0] dp[1] = max(nums[0],nums[1]): class Solution { public: int rob(vector<int>&am…

class Solution(object):    def rob(self, nums):        """        :type nums: List[int]        :rtype: int        """        n=len(nums)        if n==0:            return 0        if n==1:            return nums[0]        i=2…

题目一: 一个极其简单的动态规划. class Solution { public: int rob(vector<int>& nums) { ; // 表示没有选择当前houses ; // 表示选择了当前houses ; i < nums.size(); i++){ int temp = best0; best0 = max(best0, best1); // 没有选择当前houses,那么它等于上次选择了或没选择的最大值 best1 = temp + nums[i]; //…

你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 示例 1: 输入: [1,2,3,1] 输出: 4 解释: 偷窃 1 号房屋 (金额 = 1) ,然后偷窃 3 号房屋 (金额 = 3).   偷窃到的最高金额 = 1 + 3 = 4 . 示例 2: 输入: [2…

https://leetcode.com/problems/house-robber/ 题意: 一维数组,相加不相邻的数组,返回最大的结果. 思路: 一开始思路就是DP,用一维数组保存dp[i]保存如果偷第i间,此时可偷到多少.DP的方向不太好,所以效率很低. Runtime: 4 ms, faster than 17.53% class Solution { public: int rob(vector<int> &nums) { ; int len = nums.size(); )…

function rob(nums) { if(!nums || nums.length === 0) { return 0; } else if(nums.length < 2){ return nums[0]; } let memo = new Array(nums.length); memo[0] = nums[0]; memo[1] = Math.max(nums[0], nums[1]); for(let i = 2; i < nums.length; i++) { memo[i]…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. …