hdu 1116 Play on Words

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Play on Words HDU - 1116 （并查集 + 欧拉通路）

Play on Words HDU - 1116 Some of the secret doors contain a very interesting word puzzle. The team of archaeologists has to solve it to open that doors. Because there is no other way to open the doors, the puzzle is very important for us. There is a…

http://acm.hdu.edu.cn/showproblem.php?pid=1116 欧拉通路和欧拉回路 #include <cstdio> #include <cstring> #include <algorithm> #define maxn 1000 using namespace std; int f[maxn],in[maxn],ou[maxn],a[maxn]; bool vis[maxn]; int n; char str[maxn]; int f…

hdu 1116 欧拉回路+并查集

http://acm.hdu.edu.cn/showproblem.php?pid=1116 给你一些英文单词,判断所有单词能不能连成一串,类似成语接龙的意思.但是如果有多个重复的单词时,也必须满足这样的条件才能算YES.否则都是不可能的情况. 欧拉回路和欧拉通路的判定可以总结为如下: 1)所有的点联通 2)欧拉回路中所有点的入度和出度一样. 3)欧拉通路中起点的入度 - 出度 = 1,终点的初度 - 入度 = 1, 其他的所有点入度 = 出度: 所以用并查集搞就好了 #pragma comm…

HDU 1116 Play on Words（欧拉回路+并查集）

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1116 Play on Words Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9939 Accepted Submission(s): 3399 Problem Description Some of the secret doo…

HDU 1116 Play on Words(欧拉路径(回路))

http://acm.hdu.edu.cn/showproblem.php?pid=1116 题意:判断n个单词是否可以相连成一条链或一个环,两个单词可以相连的条件是前一个单词的最后一个字母和后一个单词的第一个字母一样. 分析前提:有(无)向图的欧拉路径判断均是基于连通图欧拉路径判断: 1.一个无向图存在欧拉路径的充要条件:头节点和尾节点度数为奇数 :中间节点度数为偶数. 2.一个有向图存在欧拉路径的充要条件:头入度==出度-1 :中间入度==出度 : 尾入度==出度+1. 欧拉回路判…

HDU 1116 Play on Words（并查集和欧拉回路）（有向图的欧拉回路）

Play on Words Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9053 Accepted Submission(s): 3125 Problem Description Some of the secret doors contain a very interesting word puzzle. The team…

POJ 1386&&HDU 1116 Play on Words(我以后再也不用cin啦!!!)

Play on Words Some of the secret doors contain a very interesting word puzzle. The team of archaeologists has to solve it to open that doors. Because there is no other way to open the doors, the puzzle is very important for us. There is a large numbe…