原题链接在这里:https://leetcode.com/problems/check-if-a-number-is-majority-element-in-a-sorted-array/ 题目: Given an array nums sorted in non-decreasing order, and a number target, return True if and only if target is a majority element. A majority element is…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 二分查找 日期 题目地址:https://leetcode-cn.com/problems/check-if-a-number-is-majority-element-in-a-sorted-array/ 题目描述 Given an array nums sorted in non-decreasing order, and a number t…

package y2019.Algorithm.array; import java.util.HashMap; import java.util.Map; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: MajorityElement * @Author: xiaof * @Description: 169. Majority Element * Given an array of…

描述 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 分析 用unordered_map来做,以元素值为…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4048 访问. 给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素. 你可以假设数组是非空的,并且给定的数组总是存在众数. 输入: [3,2,3] 输出: 3 输入: [2,2,1,1,1,2,2] 输出: 2 Given an array of size n, find the majority element. T…

Given a sorted array consisting of only integers where every element appears twice except for one element which appears once. Find this single element that appears only once. Example 1: Input: [1,1,2,3,3,4,4,8,8] Output: 2 Example 2: Input: [3,3,7,7,…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 方法一:异或 方法二:判断相邻元素是否相等 方法三:二分查找 日期 题目地址:https://leetcode.com/problems/single-element-in-a-sorted-array/description/ 题目描述 Given a sorted array consisting of only integers where every…

题目如下: 解题思路:题目要求时间复杂度是O(logN),可以尝试使用二分查找法.首先数组是有序的,而且仅有一个元素出现一次,其余均为两次.我们可以先找到数组最中间的元素,记为mid.如果mid和mid-1以及mid+1都不相同,那么mid就是single number.如果mid和mid-1相同,就要分两种情况,a.mid是奇数,single number会出现在mid的右半边:b.mid是偶数,出现在左半边.同理,如果mid和mid+1相同,那么是相反的:a.mid是奇数,出现在左半边:b.…

Given a sorted array consisting of only integers where every element appears twice except for one element which appears once. Find this single element that appears only once. Example 1: Input: [1,1,2,3,3,4,4,8,8] Output: 2 Example 2: Input: [3,3,7,7,…

Question Given a sorted array consisting of only integers where every element appears twice except for one element which appears once. Find this single element that appears only once. Example 1: Input: [1,1,2,3,3,4,4,8,8] Output: 2 Example 2: Input:…

,,,,}; //把数组的值赋给vector vector<int> vec(arr, arr+sizeof(arr)/sizeof(int)); 解法一: 时间复杂度O(n) 空间复杂度O(1) class Solution { public: void moveZeroes(vector<int>& nums) { ; //nums中,[0,...k)的元素均为非0元素 //遍历到第i个元素后,保证[0,...i)中所有非0元素 //都按照顺序排列在[0,...k)中…

题目:Given a sorted array consisting of only integers where every element appears twice except for one element which appears once. Find this single element that appears only once. 大意:给定一个已排序.全是整数int.每个元素出现两次(除了单独出现一次的元素)的数组,找到这个单独的元素. 例1: Input: [,,,,,…

540. 有序数组中的单一元素 540. Single Element in a Sorted Array 题目描述 每日一算法2019/6/14Day 42LeetCode540. Single Element in a Sorted Array…

题目描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转. ( 例如,数组 [0,0,1,2,2,5,6] 可能变为 [2,5,6,0,0,1,2] ). 编写一个函数来判断给定的目标值是否存在于数组中.若存在返回 true,否则返回 false. 示例 1: 输入: nums = [2,5,6,0,0,1,2], target = 0 输出: true 示例 2: 输入: nums = [2,5,6,0,0,1,2], target = 3 输出: false 进阶: 这是 搜索旋转排序…

24. Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it possibly have? Do you have a better hint? Suggest it! 这道题让我们…

原题链接在这里:Majority Element I,Majority Element II 对于Majority Element I 来说,有多重解法. Method 1:最容易想到的就是用HashMap 计数,数值大于n/2(注意不是大于等于而是大于),就是返回值.Time O(n), Space O(n). Method 2: 用了sort,返回sort后array的中值即可.Time O(n*logn), Space O(1). Method 3: 维护个最常出现值,遇到相同count+…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Note: The algorithm should run in linear time and in O(1) space. Example 1: Input: [3,2,3] Output: [3] Example 2: Input: [1,1,1,3,3,2,2,2] Output: [1,2] 这道题让我们求出…

原题链接在这里:https://leetcode.com/problems/majority-element/ 题目: Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority ele…

题目概述: Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 解题思路: 这个题解法很多,官方就给了七种…

Approach #1 Brute Force Intuition    We can exhaust the search space in quadratic time by checking whether each element is the majority element.Algorithm    The brute force algorithm iterates over the array, and then iterates again for each number to…

169. Majority Element Easy Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. E…

原题链接在这里:https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/ Method 1 就是找到第一个违反升序的值,就是最小值,若是没有,那么第一个值就是最小值. Time O(n). Method 2 Binary Search. 与Find Peak Element类似. while 的条件是 l < r 并且 nums[l] > nums[r], 不然 l 到 r 这一段就是sorted的. nums[mi…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 题目标签:Array 忘记说了,特地回来补充,今天看完<…

Question 169. Majority Element Solution 思路:构造一个map存储每个数字出现的次数,然后遍历map返回出现次数大于数组一半的数字. 还有一种思路是:对这个数组排序,次数超过n/2的元素必然在中间. Java实现: public int majorityElement(int[] nums) { Map<Integer, Integer> countMap = new HashMap<>(); for (int num : nums) { In…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Credits:Special thanks to @t…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 思路: [LeetCode 169]Majority Element 的拓展,这回要求的是出现次数超过三分之一次的数字咯,动动我们的大脑思考下,这样的数最多会存在几个呢,当然是2个嘛.因此,接着上一题的方…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Credits:Special thanks to @t…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路: Find k different element…