hdu1695 GCD 容斥原理】的更多相关文章

Given 5 integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y) = k. GCD(x, y) means the greatest common divisor of x and y. Since the number of choices may be very large, you're only required to output the total number of diffe…
51nod 200题辣ψ(`∇´)ψ !庆祝! 51nod 1678 lyk与gcd | 容斥原理 题面 这天,lyk又和gcd杠上了. 它拥有一个n个数的数列,它想实现两种操作. 1:将 ai 改为b. 2:给定一个数i,求所有 gcd(i,j)=1 时的 aj 的总和. Input 第一行两个数n,Q(1<=n,Q<=100000). 接下来一行n个数表示ai(1<=ai<=10^4). 接下来Q行,每行先读入一个数A(1<=A<=2). 若A=1,表示第一种操作,…
/** 题目:hdu1695 GCD 链接:http://acm.hdu.edu.cn/status.php 题意:对于给出的 n 个询问,每次求有多少个数对 (x,y) , 满足 a ≤ x ≤ b , c ≤ y ≤ d ,且 gcd(x,y) = k ,(5,7),(7,5)看做同一对, gcd(x,y) 函数为 x 和 y 的最大公约数. 本题默认:a = c = 1; 0 < a <= b <= 100,000, 0 < c <= d <= 100,000,…
题目 给定两个区间[1, b], [1, d],统计数对的个数(x, y)满足: \(x \in [1, b]\), \(y \in [1, d]\) ; \(gcd(x, y) = k\) HDU1695 题解 我们观察式子\(gcd(x,y)=k\) 很显然,\(gcd(x/k, y/k) = 1\) 我们令b < d,令x<y(避免重复计数) 分类讨论. 1) y < b 可以看出答案就是\(\sum_{i \in [1, b]} \phi(i)\) 2)\(y \in [b, d…
F - GCD Time Limit:3000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1695 Description Given 5 integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y) = k. GCD(x, y) means the greatest c…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1695 题目解析: Given 5 integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y) = k. 题目又说a==c==1,所以就是求[1,b]与[1,d]中gcd等于k的个数,因为若gcd(x,y)==z,那么gcd(x/z,y/z)==1,又因为不是z的倍数的肯定不是,所以不是z的倍数的可以直接去…
GCD Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Given integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y) = k. GCD(x, y) means the greatest…
Description Given 5 integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y) = k. GCD(x, y) means the greatest common divisor of x and y. Since the number of choices may be very large, you're only required to output the total num…
http://acm.hdu.edu.cn/showproblem.php?pid=16951 /** 大意: a<=x<=b , c<= y <= d ,求在此范围内 有多少组x,y 满足 gcd(x,y) = k ; a=c=1(题目有问题)gcd(x,y),gcd(y,x) 算一个 思路: 也就是求 1 - - b/k, 1 -- d/k 内有多少个数互素, 1. 若k =0, 则 res =0, 因为任何两个数的gcd 不可能为 0 2. 若k !=0 , 设b = b/k…
http://acm.hdu.edu.cn/showproblem.php?pid=1695 翻译题目:给五个数a,b,c,d,k,其中恒a=c=1,x∈[a,b],y∈[c,d],求有多少组(x,y)满足GCD(x,y)=k?  //(x,y)和(y,x)视作同一个 题解:既然是要x,y的最大公约数为k,那说明x/k和y/k是互质的,只需在[1,b/k]和[1,d/k]范围内找到适合的x,y即可. 特判:当k等于0时,显然没有符合的,输出结果0: #include<iostream> #in…