[1]佚名|台湾学生占领立法院 人會長大三次 第一次是發現世界不是為自己而轉的時候. 第二次是在發現即使再怎麼努力,終究還是有些事令人無能為力的時候. 第三次是在,明知道有些事可能會無能為力,但還是會儘力爭取的時候. 致這些,勇猛果敢的青春 [2]伏尔泰|读书与思考 书读得越多而不加思考,你就会觉得你知道得很多:而当你读书思考得越多的时候,你就会越清楚地看到,你知道得还很少.  [3]不可知论者 我的体会是不光是所思考或尝试建立的知识体系的不同,还存在方法论的问题,西洋强调传承,所谓站在巨人的肩…

Given a rows x cols screen and a sentence represented by a list of words, find how many times the given sentence can be fitted on the screen. Note: A word cannot be split into two lines. The order of words in the sentence must remain unchanged. Two c…

Given a rows x cols screen and a sentence represented by a list of words, find how many times the given sentence can be fitted on the screen. Note: A word cannot be split into two lines. The order of words in the sentence must remain unchanged. Two c…

Police raided his home in August and found more than 100g of marijuana. He faced a maximum sentence of three years. His arrest came amid a drug use crackdown in China which saw several celebrities arrestedtravel industry research . In June 2014, Pres…

第四部分     推理题 1.世界上每个角落的每个人都有立场,都有背景,都有推理性,能推理出一个人语言的真意,才成就了真正的推理能力: 2.换言之,如果你能通过一个人的说话推理出其身份职业,你的推理能力更上一层楼. 一 . 临门一脚 1. “I believe in human ingenuity – that when we decide on a task to be done, no matter how daunting it may seem at the beginning, we…

首先想到的是直接做,然后TLE. public class Solution { public int wordsTyping(String[] sentence, int rows, int cols) { int m = sentence.length; int res = 0; int c = 0; int left = cols; for(int i = 0; i < rows;) { if(sentence[c%m].length() <= left) { if(c%m == m-1…

Algorithm: Refrence from one ICML15 paper: Word Mover's Distance. 1. First use Google's word2vec tool to get distributed word representing aka. word vectors. 2. Then use earth mover's distance as similarity measure metric. 3. Solve the EMD problem as…

A. Whose sentence is it? Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/312/problem/A Description One day, liouzhou_101 got a chat record of Freda and Rainbow. Out of curiosity, he wanted to know which sentences were said…

题解转自:http://blog.csdn.net/dyx404514/article/details/8807440 2012杭州网络赛的一道题,后缀数组后缀自己主动机都行吧. 题目大意:给一个字符串S和一系列字符串T1~Tn,问在S中有多少个不同子串满足它不是T1~Tn中随意一个字符串的子串. 思路:我们先构造S的后缀自己主动机,然后将每个Ti在S的SAM上做匹配,类似于LCS,在S中的每个状态记录一个变量deep,表示T1~Tn,在该状态能匹配的最大长度是多少,将每个Ti匹配完之后,我们将…

Given two sentences words1, words2 (each represented as an array of strings), and a list of similar word pairs pairs, determine if two sentences are similar. For example, words1 = ["great", "acting", "skills"] and words2 = [&…