#-*- coding: UTF-8 -*-#双栈法class Queue(object):    def __init__(self):        """        initialize your data structure here.        """        self.inStack=[]        self.outStack=[]            def push(self, x):        "…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Python解法 Java解法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/implement-queue-using-stacks/ Total Accepted: 42648 Total Submissions: 125482 Difficulty: Easy 题目描述 Implement t…

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题目: Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes:…

#-*- coding: UTF-8 -*- #题意:大海捞刀,在长字符串中找出短字符串#AC源码:滑动窗口双指针的方法class Solution(object):    def strStr(self, hayStack, needle):        """        :type haystack: str        :type needle: str        :rtype: int        """        if…

#-*- coding: UTF-8 -*-class Stack(object):    def __init__(self):        """        initialize your data structure here.        """        self.inQueue=[]        self.outQueue=[]    def push(self, x):        """…

155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } void push(int x) { if(s1.empty() && s2.empty()){ s1.push(x); s2.push(x); } else{ if(x < s2.top()){ s1.push(x); s2.push(x); } else{ s1.push(x); s2…

1. 232 Implement Queue using Stacks 1.1 问题描写叙述 使用栈模拟实现队列.模拟实现例如以下操作: push(x). 将元素x放入队尾. pop(). 移除队首元素. peek(). 获取队首元素. empty(). 推断队列是否为空. 注意:仅仅能使用栈的标准操作,push,pop,size和empty函数. 1.2 方法与思路 本题和用队列实现栈思路一样,设两个辅助栈stk1和stk2. push(x): 将x入栈stk1. pop(): 依次将stk1…

232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front o…

Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes: You…