A pair of numbers has a unique LCM but a single number can be the LCM of more than one possiblepairs. For example 12 is the LCM of (1, 12), (2, 12), (3,4) etc. For a given positive integer N, thenumber of different integer pairs with LCM is equal to N…

Problem F LCM Cardinality Input: Standard Input Output: Standard Output Time Limit: 2 Seconds A pair of numbers has a unique LCM but a single number can be the LCM of more than one possible pairs. For example 12 is the LCM of (1, 12), (2, 12), (3,4)…

LCM Cardinality Input: Standard Input Output: Standard Output Time Limit: 2 Seconds A pair of numbers has a unique LCM but a single number can be the LCM of more than one possible pairs. For example 12 is the LCM of (1, 12), (2, 12), (3,4) etc. For a…

题目链接 写写,就ok了. #include <cstdio> #include <cstring> #include <string> #include <cmath> #include <ctime> #include <cstdlib> #include <iostream> using namespace std; #define MOD 1000000 #define LL long long ]; ]; int…

题意:给出数n,求有多少组A,B的最小公约数为n; 思路:3000ms,直接暴力寻找,找到所有能把n整除的数 pi, 枚举所有pi 代码: #include <iostream> #include <cstdio> #include <vector> #define ll long long using namespace std; ll gcd(ll a,ll b) { ) return a; else return gcd(b,a%b); } int main()…

I I U C   O N L I N E   C  Problem D: GCD LCM Input: standard input Output: standard output The GCD of two positive integers is the largest integer that divides both the integers without any remainder. The LCM of two positive integers is the smallest…

LCM Cardinality Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Description   Problem FLCM CardinalityInput: Standard Input Output: Standard Output Time Limit: 2 Seconds A pair of numbers has a unique LCM but a si…

我一直相信这道题有十分巧妙的解法的,去搜了好多题解发现有的太过玄妙不能领会. 最简单的就是枚举n的所有约数,然后二重循环找lcm(a, b) = n的个数 #include <cstdio> #include <vector> #include <algorithm> using namespace std; ? a : gcd(b, a % b); } int lcm(int a, int b) { return a / gcd(a, b) * b; } int ma…

这题就是 LightOJ - 1236 解析去看这个把https://www.cnblogs.com/WTSRUVF/p/9185140.html 贴代码了: #include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <set> #include <vector> #include…

链接: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1229 题意: 大街上到处在卖彩票,一元钱一张.购买撕开它上面的锡箔,你会看到一个漂亮的图案.图案有n种,如果你收集到所有n(n≤33)种彩票,就可以得大奖.请问,在平均情况下,需要买多少张彩票才能得到大奖呢?如n=5时答案为137/12. 分析: 已有k个图案,令s=k/n,拿一个…