题目传送门 细节较多的构造题. 解决思路 题目中虽然说是无根树,但我们可以钦定这棵树的根为 1,方便构造,这是不影响结果的. 以下记给定的三段长度为 \(a,b,c\) . 先考虑无解的情况. 首先,给出的三个距离,任意两者之和必须大于等于第三者,否则显然无解. 其次,用到的边数不能\(\ge n\). 最后,两个节点的 \(\text{LCA}\) 到根节点的距离 (绿色) 是整数,两节点之间最短距离 (蓝色) 也是整数,而 \(a+b+c\) 正好是蓝色绿色各算两次,所以 \(a+b+c\)…
题面传送门 解决思路 题目中虽然说是无根树,但我们可以钦定这棵树的根为节点 \(1\),方便构造,这是不 影响结果的. 以下记给定的三段长度为 \(a,b,c\). 先考虑无解的情况. 首先,给出的三个距离,任意两者之和必须大于等于第三者,否则显然无解. 其次,用到的边数不能 \(\ge n\). 最后,两个节点的 \(\text{LCA}\) 到根节点的距离 (绿色) 是整数,两节点之间最短距离 (蓝色) 也是整数,而 \(a+b+c\) 正好是蓝色绿色各算两次,所以 \(a+b+c\) 必须…
Build a tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 946    Accepted Submission(s): 369 Problem Description HazelFan wants to build a rooted tree. The tree has n nodes labeled 0 to n−1…
/** 题目:hdu6121 Build a tree 链接:http://acm.hdu.edu.cn/showproblem.php?pid=6121 题意:n个点标号为0~n-1:节点i的父节点为floor((i-1)/k); 0是根节点. 求这个树的所有节点为根的子树的节点数的异或和. 思路:模拟 可以发现k = min(k,n-1):即:k>=n-1时候结果一样. 然后画图可以发现是一个满k叉树(叶子不一定满). 然后发现:如果这是一个叶子也满的k叉树,那么直接就可以计算出结果. 当不…
地址:http://acm.split.hdu.edu.cn/showproblem.php?pid=6121 题面: Build a tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 1240    Accepted Submission(s): 509 Problem Description HazelFan wants…
题目链接:Balanced Binary Tree | LeetCode OJ Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more tha…
题目链接 Problem Description HazelFan wants to build a rooted tree. The tree has n nodes labeled 0 to n−1, and the father of the node labeled i is the node labeled ⌊i−1k⌋. HazelFan wonders the size of every subtree, and you just need to tell him the XOR…
HazelFan wants to build a rooted tree. The tree has nn nodes labeled 0 to n−1, and the father of the node labeled i is the node labeled  . HazelFan wonders the size of every subtree, and you just need to tell him the XOR value of these answers. Input…
分享一段用 <ul>和<li>标签实现tree的代码,可能写的不是很好,如果大家有更好的希望和小颖分享下.嘻嘻 啦啦啦,代码看这里喽: <div class="tree"> <nav class='navbar'> <ul class='nav nav-stacked'> <template v-for='item in menus'> <li role='presentation' v-if='!item.…
Roadmap Decision Tree Hypothesis Decision Tree Algorithm Decision Tree Heuristics in C&RT Decision Tree in Action Summary…