824. Goat Latin - LeetCode】的更多相关文章

Questioin 824. Goat Latin Solution 题目大意:根据要求翻译句子 思路:转换成单词数组,遍历数组,根据要求转换单词 Java实现: 用Java8的流实现,效率太低 public String toGoatLatin(String S) { final String[] arr = S.split(" "); final int[] idx = {0}; return Arrays.stream(S.split(" ")) .map(s…
problem 824. Goat Latin solution class Solution { public: string toGoatLatin(string S) { unordered_set<char> vowel{ 'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U' };// istringstream iss(S);// string res, word; ; while(iss >> word) { res += ]…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/goat-latin/description/ 题目描述 A sentence S is given, composed of words separated by spaces. Each word consists of lowercase and uppercase l…
题目要求 A sentence S is given, composed of words separated by spaces. Each word consists of lowercase and uppercase letters only. We would like to convert the sentence to "Goat Latin" (a made-up language similar to Pig Latin.) The rules of Goat Lat…
A sentence S is given, composed of words separated by spaces. Each word consists of lowercase and uppercase letters only. We would like to convert the sentence to "Goat Latin" (a made-up language similar to Pig Latin.) The rules of Goat Latin ar…
Description A sentence S is given, composed of words separated by spaces. Each word consists of lowercase and uppercase letters only. We would like to convert the sentence to "Goat Latin" (a made-up language similar to Pig Latin.) The rules of G…
[抄题]: A sentence S is given, composed of words separated by spaces. Each word consists of lowercase and uppercase letters only. We would like to convert the sentence to "Goat Latin" (a made-up language similar to Pig Latin.) The rules of Goat La…
题目标签:String 首先把vowel letters 保存入 HashSet. 然后把S 拆分成 各个 word,遍历每一个 word: 当 word 第一个 字母不是 vowel 的时候,把第一个char 加到最后: 然后添加“ma” 和 “a“ 到最后: 添加新的"a": 把新的 word 加入 result,还要记得加入空格. Java Solution: Runtime beats 62.66% 完成日期:10/12/2018 关键词:String 关键点:利用HashSe…
class Solution { public: string toGoatLatin(string S) { S.push_back(' '); //add a space that the loop can deal with the last word ,'a'); // string to add 'a' unordered_set<char> vowel={'a','e','i','o','u','A','E','I','O','U'}; ; int len=S.size(); ;…
这是悦乐书的第322次更新,第344篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第192题(顺位题号是824).给出句子S,由空格分隔的单词组成.每个单词仅由小写和大写字母组成.我们想将句子转换为"Goat Latin"(一种类似于Pig Latin的伪造语言). 山羊拉丁的规则如下: (1)如果单词以元音(a,e,i,o或u)开头,则在单词的末尾附加"ma".例如,"apple"这个词就变成了"appl…