一.题目大意 https://leetcode.cn/problems/longest-word-in-dictionary-through-deleting 给你一个字符串 s 和一个字符串数组 dictionary ,找出并返回 dictionary 中最长的字符串,该字符串可以通过删除 s 中的某些字符得到. 如果答案不止一个,返回长度最长且字母序最小的字符串.如果答案不存在,则返回空字符串. 示例 1: 输入:s = "abpcplea", dictionary = [&quo…

524. 通过删除字母匹配到字典里最长单词 给定一个字符串和一个字符串字典,找到字典里面最长的字符串,该字符串可以通过删除给定字符串的某些字符来得到.如果答案不止一个,返回长度最长且字典顺序最小的字符串.如果答案不存在,则返回空字符串. 示例 1: 输入: s = "abpcplea", d = ["ale","apple","monkey","plea"] 输出: "apple" 示例…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

1. 具体题目 给定一个字符串和一个字符串字典,找到字典里面最长的字符串,该字符串可以通过删除给定字符串的某些字符来得到.如果答案不止一个,返回长度最长且字典顺序最小的字符串.如果答案不存在,则返回空字符串. 示例 1: 输入: s = "abpcplea", d = ["ale","apple","monkey","plea"] 输出:  "apple" 2. 思路分析 遍历字符串数组…

题目描述 给定一个字符串和一个字符串字典,找到字典里面最长的字符串,该字符串可以通过删除给定字符串的某些字符来得到.如果答案不止一个,返回长度最长且字典顺序最小的字符串.如果答案不存在,则返回空字符串. 示例 1: 输入: s = "abpcplea", d = ["ale","apple","monkey","plea"] 输出: "apple" 示例 2: 输入: s = "…

https://leetcode.com/problems/longest-word-in-dictionary-through-deleting/ Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than on…

[LeetCode]Longest Word in Dictionary through Deleting 解题报告 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/longest-word-in-dictionary-through-deleting/#/description 题目描述: Given a string and a string dictionary, find the longest string in the di…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

目录 题目链接 注意点 解法 小结 题目链接 Longest Word in Dictionary through Deleting - LeetCode 注意点 长度一样的字符串要按字典序返回较小的 解法 解法一:遍历字典中的单词,用一个变量i来记录单词中的某个字母的位置,我们遍历给定字符串,如果遍历到单词中的某个字母来,i自增1,如果没有,就继续往下遍历.这样如果最后i和单词长度相等,说明单词中的所有字母都按顺序出现在了字符串s中.如果能得到,而且单词长度大于等于结果ret的长度,我们再看是…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

1. Question Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest l…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

b.compareTo(a) 这个函数是比较两个值得大小,如果b比a大,那么返回1 如果小,那么返回-1,相等返回0 如果比较的是字符串,那么比较字典编纂顺序,b靠前返回-1,靠后返回1 这个题的核心虽然是hashtable,但是这个方法还是很重要的,因为自己实现比较字符串很麻烦 /* 用一个Hashset来判断子串是不是在集合里 然后遍历出最长的就行 长度相同的用compareTo方法判断谁的字典顺序靠前 这个题最难的感觉其实是不知道compareTo方法,自己实现还挺麻烦的 */ publi…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

problem 720. Longest Word in Dictionary 题意: solution1: BFS; class Solution { public: string longestWord(vector<string>& words) { string res = ""; unordered_set<string> s(words.begin(), words.end()); queue<string> q; for(aut…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力查找 排序 日期 题目地址:https://leetcode.com/problems/longest-word-in-dictionary/description/ 题目描述 Given a list of strings words representing an English Dictionary, find the longest wo…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4120 访问. 给出一个字符串数组words组成的一本英语词典.从中找出最长的一个单词,该单词是由words词典中其他单词逐步添加一个字母组成.若其中有多个可行的答案,则返回答案中字典序最小的单词. 若无答案,则返回空字符串. 输入: words = ["w","wo","wor","worl"…

这是悦乐书的第303次更新,第322篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第171题(顺位题号是720).给出表示英语词典的字符串单词数组,找到单词中长度最长的单词,此单词可以通过数组中的其他单词一次次构建一个字符而得来.如果有多个可能的答案,则返回字典顺序最小的最长单词.如果没有答案,则返回空字符串.例如: 输入:words = ["w","wo","wor","worl","…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

［抄题］: Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smal…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: string longestWord(vector<string>& words) { unordered_set<string> siset(words.begin(),words.end()); string res; for(string s:words) { i…

给出一个字符串数组words组成的一本英语词典.从中找出最长的一个单词,该单词是由words词典中其他单词逐步添加一个字母组成.若其中有多个可行的答案,则返回答案中字典序最小的单词. 若无答案,则返回空字符串. 示例 1: 输入: words = ["w","wo","wor","worl", "world"] 输出: "world" 解释: 单词"world"可由&…

这道题相似  Word Break 推断能否把字符串拆分为字典里的单词 @LeetCode 只不过要求计算的并不不过能否拆分,而是要求出全部的拆分方案. 因此用递归. 可是直接递归做会超时,原因是LeetCode里有几个非常长可是无法拆分的情况.所以就先跑一遍Word Break,先推断能否拆分.然后再进行拆分. 递归思路就是,逐一尝试字典里的每个单词,看看哪一个单词和S的开头部分匹配,假设匹配则递归处理S的除了开头部分,直到S为空.说明能够匹配. Given a string s and a…

一. 题目描写叙述 Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: • Only one letter can be changed at a time • Each intermediate word must exist in the dictionary For exampl…

原题链接在这里:https://leetcode.com/problems/longest-string-chain/ 题目: Given a list of words, each word consists of English lowercase letters. Let's say word1 is a predecessor of word2 if and only if we can add exactly one letter anywhere in word1 to make i…

A string such as "word" contains the following abbreviations: ["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "…