public RandomListNode copyRandomList(RandomListNode head) { /* 深复制,就是不能只是复制原链表变量,而是做一个和原来链表一模一样的新链表, 每一个节点都是新建的,而不是指向就节点 这个题的难点在于:随机节点. 随机节点有可能指向后边还没有建立的节点,这就没法指. 方法一:一一对应地记录每个新旧节点的映射关系,在常规节点建立后,就去查哈希表,找到对应 新节点的旧节点的random,就是新节点的random */ if (head==nu…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Example 1: Input: {"$id":"1","next":{"$id":"2&…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道题的难点在于如何处理随机指针,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果在生成一个新节点给其随机指针赋值时,都去遍历原链表的话…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道链表的深度拷贝题的难点就在于如何处理随机指针的问题,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果我们在每生成一个新节点给其随机指…

题目描述: 中文: 给定一个链表,每个节点包含一个额外增加的随机指针,该指针可以指向链表中的任何节点或空节点. 要求返回这个链表的深拷贝. 示例: 输入:{"$id":"1","next":{"$id":"2","next":null,"random":{"$ref":"2"},"val":2},"…

职务地址:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题意:对一个有回路的链表的深复制 解题:这道题我AC了之后才发现理解错了题意,然后就參考了以下这篇文章. 假设想看这道题的解题思路的话,请移步http://www.2cto.com/kf/201310/253477.html 拓展:假如题目给的节点不是链表的头节点.而是链表中的随意一个节点,在保证从给的点能遍历所有节点的情况下,深复制这个链表. 那么该怎么做呢…

Copy List with Random Pointer 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/copy-list-with-random-pointer/description/ Description A linked list is given such that each node contains an additional random pointer which could point to any node in the…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这题用map做其实比较简单,但是一开始没想明白越想越乱,最后看了下别人的实现,思路还是很清晰的,代码如下所示: /** * Definition for singly-li…

python代码如下: # Definition for singly-linked list with a random pointer. # class RandomListNode(object): # def __init__(self, x): # self.label = x # self.next = None # self.random = None class Solution(object): def copyRandomList(self, head): ""&q…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 我们在Java for LeetCode 133 Clone Graph题中做过图的复制,本题和图的复制十分类似,JAVA实现如下: public Random…