hdu1455Sticks(经典dfs+剪枝)

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hdu1455Sticks(经典dfs+剪枝)

Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13807 Accepted Submission(s): 4270 Problem Description George took sticks of the same length and cut them randomly until all parts becam…

poj 1011 ：Sticks (dfs+剪枝)

题意:给出n根小棒的长度stick[i],已知这n根小棒原本由若干根长度相同的长木棒(原棒)分解而来.求出原棒的最小可能长度. 思路:dfs+剪枝.蛮经典的题目,重点在于dfs剪枝的设计.先说先具体的实现:求出总长度sum和小棒最长的长度max,则原棒可能的长度必在max~sum之间,然后从小到大枚举max~sum之间能被sum整除的长度len,用dfs求出所有的小棒能否拼凑成这个长度,如果可以,第一个len就是答案. 下面就是关键的了,就是这道题dfs的实现和剪枝的设计: 1.以一个小棒为开头…

poj1011（DFS+剪枝）

题目链接:https://vjudge.net/problem/POJ-1011 题意:给定n(<=64)条木棍的长度(<=50),将这些木棍刚好拼成长度一样的若干条木棍,求拼出的可能的最小长度. 思路:经典的DFS剪枝题,这道题的剪枝技巧很关键. 数据不大,可以想到枚举木棍所有可能的长度,然后利用dfs来查找所有可能的搭配情况,dfs的参数len表示当前的木棍长度,rest表示还需要的长度,pos表示当前搜到的下标,num表示原始木棍中剩余没有匹配的数量,搜索的终止条件为rest==0&am…

*HDU1455 DFS剪枝

Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9779 Accepted Submission(s): 2907 Problem Description George took sticks of the same length and cut them randomly until all parts became…

POJ 3009 DFS+剪枝

POJ3009 DFS+剪枝原题: Curling 2.0 Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 16280 Accepted: 6725 Description On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from our…

poj 1724:ROADS（DFS + 剪枝）

ROADS Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 10777 Accepted: 3961 Description N cities named with numbers 1 ... N are connected with one-way roads. Each road has two parameters associated with it : the road length and the toll…

DFS(剪枝) POJ 1011 Sticks

题目传送门 /* 题意:若干小木棍,是由多条相同长度的长木棍分割而成,问最小的原来长木棍的长度: DFS剪枝:剪枝搜索的好题!TLE好几次,终于剪枝完全! 剪枝主要在4和5:4 相同长度的木棍不再搜索:5 若新的搜索连第一条都没组合出来,直接break: 详细解释:http://blog.csdn.net/lyy289065406/article/details/6647960 http://www.cnblogs.com/devil-91/archive/2012/08/03/2621787.…