HDU 1548 A strange lift(BFS)】的更多相关文章

Problem Description There is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every floor.The lift have just two buttons: up and down.When you at floor i,if you press the button "UP"…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1548 A strange lift Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21754    Accepted Submission(s): 7969 Problem Description There is a strange li…
https://vjudge.net/problem/HDU-1548 题意: 电梯每层有一个不同的数字,例如第n层有个数字k,那么这一层只能上k层或下k层,但是不能低于一层或高于n层,给定起点与终点,要求出最少要按几次键. 思路: 可以用BFS,也可以用迪杰斯特拉算法. #include<iostream> #include<cstring> #include<algorithm> #include<vector> using namespace std;…
题目链接 Problem Description There is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every floor.The lift have just two buttons: up and down.When you at floor i,if you press the button "UP…
题目链接: 传送门 A strange lift Time Limit: 1000MS     Memory Limit: 32768 K Description There is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every floor.The lift have just two buttons: up and…
A strange lift Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18723    Accepted Submission(s): 6926 Problem Description There is a strange lift.The lift can stop can at every floor as you want,…
( ̄▽ ̄)" //dijkstra算法, //只是有效边(即能从i楼到j楼)的边权都为1(代表次数1): //关于能否到达目标楼层b,只需判断最终lowtime[b]是否等于INF即可. #include<iostream> #include<cstdio> using namespace std; const int INF=10e7; ; int k,minn; int K[MAXN]; int cost[MAXN][MAXN]; int lowtime[MAXN];…
题意:给出一个电梯,给出它的层数f,给出起点s,终点g,以及在每一层能够上或者下w[i]层,问至少需要按多少次按钮到达终点. 和POJ catch that cow一样,直接用了那一题的代码,发现一直wa, 后来才发现,POJ catch that cow是单组输入的,所以每次调用的时候不用清空队列,而这一题一次输入有多组数据--- 用这个清空队列 while(!q.empty()) q.pop(); #include<iostream> #include<cstdio> #inc…
HDU.2612 Find a way (BFS) 题意分析 圣诞节要到了,坤神和瑞瑞这对基佬想一起去召唤师大峡谷开开车.百度地图一下,发现周围的召唤师大峡谷还不少,这对基佬纠结着,该去哪一个...坤神:我要去左边的这个(因为离自己比较近 哈哈~)..瑞瑞:我要去右边的这个(因为离自己比较近 嘿嘿~) --..这对基佬闹矛盾了,开车有危险了! 为了不让他们去召唤师大峡谷坑人,riot决定让他们去X召唤师大峡谷,保证他俩所走的路程和最短.每走一个点需要花费11分钟,输出他们一共花费多少时间(最短时…
http://acm.hdu.edu.cn/showproblem.php?pid=1548 A strange lift Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11341    Accepted Submission(s): 4289 Problem Description There is a strange lift.T…