Leetcode 21 Merge Two Sorted Lists 链表】的更多相关文章

合并两个已排序的链表,考到烂得不能再烂的经典题,但是很多人写这段代码会有这样或那样的问题 这里我给出了我的C++算法实现 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相…
合并链表 Runtime: 4 ms, faster than 100.00% of C++ online submissions for Merge Two Sorted Lists. class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { //1 2 4 . 1 3 4 ListNode *res = ); ListNode *cur = res; while (l1 != NULL &&am…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 中文:将两个有序链表合并为一个新的有序链表并返回.新链表…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题目 合并两个链表 思路 用dummy, 因为需要对头结…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目标签:Linked List 题目给了我们两个lists,让我们有序的合并两个 lists. 这题利用递归可以从list 的最后开始向前链接nodes,代码很简洁,清楚. Java Solution: Runti…
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 分析: 将两个有序链表合并为一个新的有序链表并返…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 list顺序合并就可以了 /** * Definitio…
题目描述: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题思路: 题目的意思是将两个有序链表合成一个有序链表. 逐个比较加入到新的链表即可. 代码如下: public static ListNode mergeTwoLists(ListNode l1, Li…