Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路一: BigInteger!!! JAVA实现如下: import java.math.BigInteger; public class Solution { static pu…

题目要求:Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 分析: 参考网址:http://blog.csdn.net/pickless/article/details/9235907 利用竖式的思想,…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative.     各个位相乘,保存在数组中,最后再处理进位. 如 123*456     4,5,6      8,10,12         12,15,18…

转载:43. Multiply Strings 题目描述 就是两个数相乘,输出结果,只不过数字很大很大,都是用 String 存储的.也就是传说中的大数相乘. 解法一 我们就模仿我们在纸上做乘法的过程写出一个算法. 个位乘个位,得出一个数,然后个位乘十位,全部乘完以后,就再用十位乘以各个位.然后百位乘以各个位,最后将每次得出的数相加.十位的结果要补 1 个 0 ,百位的结果要补两个 0 .相加的话我们可以直接用之前的大数相加.直接看代码吧. public String multiply(Stri…

题目描述: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路: 设置数组记录单个位置相乘的结果,最后负责相加进位. 代码如下: public class Solution { public String multiply(St…

给定两个以字符串表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积.注意:    num1 和 num2 的长度均小于110.    num1 和 num2 均只包含数字 0-9.    num1 和 num2 均不以零开头.    你不能使用任何内置的大整数库或直接将输入转换为整数.详见:https://leetcode.com/problems/multiply-strings/description/ Java实现: class Solution { public…

Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…

Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters.…

题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路比较简单,不多说啦 几个需要注意的点: 1. 高位多个为0的,需要进行判断 2. 如果乘数为0的话,可以直接跳过,能节省不少时间 3. string 的两个使用 1) 创建有…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路:直观思路,就是模拟乘法过程.注意进位.我写的比较繁琐. string multiply(string num1, string num2) { vector<int> v1, v…