Find Kth Largest Number public class Solution { public int findKthLargest(int[] nums, int k) { return findK(nums,nums.length - k,0,nums.length-1); } private int findK(int[] nums,int k, int start, int end){ int parti = nums[start],i=start,m=start; for…

这里我们可以考虑将 n 数之和降低为一个数加上 n-1 数之和的问题.依次降低 ,最低是二数之和的问题 ,二数之和问题容易解决.主要在于从 n 到 n-1 的过程需要理解 :下列代码中前几个 if 是对特殊情况的处理 :通过新的 target = target - nums[i] 进行参数修改再次调用 nsum()方法即递归 . def nsum(nums, target, n, result, results): #求n数之和=target if len(nums) < n or n < 2…

目录 一.上节课回顾 (一)if判断 1.单分支结构 2.双分支结构 3.多分支结构 (二)for循环 1.for + break 2.for + continue 3.for循环嵌套 (三)robust 健壮性/撸棒形 二.异常处理 三.leetcode 四.字符串内置方法 (1) 索引取值 (2) 切片 (3) 成员运算 (4) for循环 (5) len() (6) strip() (7) lstrip()/rstrip() (8) startswith()/endswith() (9)…

Given four lists A, B, C, D of integer values, compute how many tuples (i, j, k, l) there are such that A[i] + B[j] + C[k] + D[l] is zero. To make problem a bit easier, all A, B, C, D have same length of N where 0 ≤ N ≤ 500. All integers are in the r…

Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: Elements in a quadruplet (a,b,c,d) must be in non-descending order.…

题目 Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.s…

Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain duplicate quadruplets. For exampl…

leetcode 第四天 2018年1月4日 15.(628)Maximum Product of Three Numbers JAVA class Solution { public int maximumProduct(int[] nums) { Arrays.sort(nums); return (nums[0]*nums[1]*nums[nums.length-1])>(nums[nums.length-1]*nums[nums.length-2]*nums[nums.length-3]…

Imagine you have a special keyboard with the following keys: Key 1: (A): Print one 'A' on screen. Key 2: (Ctrl-A): Select the whole screen. Key 3: (Ctrl-C): Copy selection to buffer. Key 4: (Ctrl-V): Print buffer on screen appending it after what has…

这是悦乐书的第314次更新,第335篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第183题(顺位题号是783).给定具有根节点值的二叉搜索树(BST),返回树中任何两个不同节点的值之间的最小差值.示例: 给定的树[4,2,6,1,3,null,null]由下图表示: 4 / \ 2 6 / \ 1 3 输出:1 说明:请注意,root是TreeNode对象,而不是数组.该树中的任意节点最小差值为1,它发生在节点1和节点2之间,也发生在节点3和节点2之间. 注意:…