题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8185    Accepted Submission(s): 4691 Problem Description Suppose that we have a squa…

http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6756    Accepted Submission(s): 3829 Problem Description Suppose that we have a square ci…

Fire Net Problem Description Suppose that we have a square city with straight streets. A map of a city is a square board with n rows and n columns, each representing a street or a piece of wall. A blockhouse is a small castle that has four openings t…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12920    Accepted Submission(s): 7840 Problem Description Suppose that we have a squa…

Fire Net Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 17669    Accepted Submission(s): 10749 Problem Description Suppose that we have a square city with straight streets. A map of a city is a…

在一张地图上建立碉堡(X),要求每行没列不能放两个,除非中间有强挡着.求最多能放多少个碉堡 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #define N 5 using namespace std; int n,ans; char maps[N][N]; int judge(int x,int y) { int i; if(maps[x][y]=='X'…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1045 题目大意: 给你一幅n*n的图,再给你一些点,这些点的上下左右不能再放其他点,除非有墙('X')隔着,问最多可以放多少个这样的点. 思路: 由于n不大于4,最多16个点,想到可以二进制枚举子集,然后逐个判断每个子集的可行性. #include<iostream> #include<string> #include<vector> #include<cstdio&…

原题链接:点击!   大致题意:白块表示可以放置炮台的位置——每个炮台可以攻击到上下左右的直线上的炮台(也就是说在它的上下左右直线上不可以再放置炮台,避免引起互相攻击),黑块表示隔离墙的位置——不可放置并且可以阻挡炮火:求对于一个最大4*4的格子来说,最大的放置炮台的个数是多少. 简单分析: 简单的dfs();由于本题地图很小,不用考虑太多,尽情暴力即可.先把DFS枝干画出来,然后枝叶就用函数来具体实现. AC代码:(附注释) #include <iostream> #include<s…

Fire Net Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15653    Accepted Submission(s): 9474 题目链接:acm.hdu.edu.cn/showproblem.php?pid=1045 Description: Suppose that we have a square city with s…

题意 有一个 n*n 的图,. 代表空白区域,X 代表墙,现在要在空白区域放置结点,要求同一行同一列只能放一个,除非有墙阻隔,问最多能放多少个点 思路 只有在墙的阻隔情况下,才会出现一行/列出现多个点的情况,那么可以考虑进行缩点,将同一行且没有墙体阻隔的区域缩成一个点,放到左点集中,将同一列且没有墙体阻隔的区域缩成一个点,放到右点集中,从而建成一个二分图 假设 i 为行编号,j 为列编号,若 i-j 之间存在一条边,就相当于在方格 (i,j) 上放了一个点,这个假设使得在没有墙体阻隔的情况下,i…

在论文<SQUEEZENET: ALEXNET-LEVEL ACCURACY WITH 50X FEWER PARAMETERS AND <0.5MB MODEL SIZE>中,作者对模型进行压缩的核心我感觉就是利用许多的Fire Module模块来替代原来的conv+pool 其中所谓的"Fire Module"就是一种专门设计的结构,具体而言是由两部分构成:sequeeze以及后面连接的enpand两部分,其中的sequeeze部分是卷积核为1*1的卷积层,后面的…

Fire Game Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice FZU 2150 Description Fat brother and Maze are playing a kind of special (hentai) game on an N*M board (N rows, M columns). At the beginning,…

Fire 分析: 首先,明确题意:b1,b2,--,bn 交换为b2,--,bn,b1,但这并不是意味着只能从b1开始交换,(这点从样例中可以看出),并且也不意味着交换的必须是连续的一串,可以是几个单点,如: 原序列:1 2 3 4 5,交换(1 3 5)后 新序列:3 2 5 4 1 交换时必须按照环的方式顺时针或逆时针转动,这并没有限制,只需要一个位置移动到另一个位置时将他顶替掉,他去找他自己应该到的位置就好了,最终是按一个环的移动方式移动,但不一定是从左到右或从右到左,方向交叉. 所以:…

Fire Eye是一款轻量级简单易用的Android校验库. FireEye 2.0 在 1.0 的基础上,全部重写了代码,并优化了架构,性能上和逻辑上都大大提升.只需要几行代码,即可验证用户输入,并且将验证错误反馈给用户.它内置了大量常用的验证类型,足以满足你的功能需求. Gradle 依赖 Add dependency dependencies { compile 'com.github.yoojia:fire-eye:2.2@aar' } Maven <dependency> <g…

FZU 2150 Fire Game Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u   Description Fat brother and Maze are playing a kind of special (hentai) game on an N*M board (N rows, M columns). At the beginning, each grid of this bo…

题目大意:在一个N*M的迷宫内,J代表某人(只有一个),F代表火(可能不只一个),#代表墙,火每分钟会向四周除了墙以外的地方扩散一层,问人能否在没被火烧到 之前逃出迷宫,若能逃出输出最短时间.很明显的bfs.但由于火到达的地方人不能抵达,故需先对火进行bfs,标记后若人在火烧到之前抵达即可.最后逃出时间需要加一, 因为当时只是抵达边界,若逃出时间需加一. #include <stdio.h> #include <queue> #include <string.h> #i…

在上周Amazon也耐不住加入了手机竞争行列之中,发布了自己的Fire Phone,于是Android家族又多了一位变种成员,Android系统的碎片化程度也进一步加剧.因为工作的关系,我有幸在上个月就得到了一部工程机为其做提前开发,不过因为政策原因所以到现在才能来谈谈对这部新手机的看法. 对于Fire Phone的功能以及外观,官方网站和各家技术网站都有了详尽的介绍和报道,再者因为我拿到的是工程机,无法体现到完备的功能展现,因此本篇文章谈的主要是Fire Phone对于开发者而言所要面对的问题…

Fire! Time Limit:1000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Description   Problem B: Fire! Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a fi…

Problem 2150 Fire Game Accept: 145    Submit: 542 Time Limit: 1000 mSec    Memory Limit : 32768 KB Problem Description Fat brother and Maze are playing a kind of special (hentai) game on an N*M board (N rows, M columns). At the beginning, each grid o…

Fire Net Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5863    Accepted Submission(s): 3280 Problem Description Suppose that we have a square city with straight streets. A map of a city is a s…

题目传送门 /* 题意:在一个矩阵里放炮台,满足行列最多只有一个炮台,除非有墙(X)相隔,问最多能放多少个炮台 搜索(DFS):数据小,4 * 4可以用DFS,从(0,0)开始出发,往(n-1,n-1)左下角走,x = cnt / n; y = cnt % n; 更新坐标, 直到所有点走完为止,因为从左边走到右边,只要判断当前点左上方是否满足条件就可以了 注意:当前点不能放炮台的情况也要考虑 g[x][y] == 'o'; 的错误半天才检查出来:) */ #include <cstdio> #…

Fire! Time Limit: 5000MS   Memory Limit: 262144KB   64bit IO Format: %lld & %llu Description Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a fire escape plan. Help Joe esca…

Description: You are trapped in a building consisting of open spaces and walls. Some places are on fire and you have to run for the exit. Will you make it?At each second, the fire will spread to all open spaces directly connected to the North, South,…

http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1045 Description Suppose that we have a square city with straight streets. A map of a city…

题目链接 http://vjudge.net/contest/121377#problem/J Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a fire escape plan. Help Joe escape the maze. Given Joe's location in the maze…

题目:Hire and Fire 题目翻译成数据结构就是:建树,加结点,删除结点,打印结点.只有删除结点稍微复杂点,因为删除设计掉树的调整. 首先要考虑树怎么存储才能使解题更顺手. 1.我们要存储每个结点的孩子,父亲和名字.存储孩子是因为第一个孩子可能会“升级”,存储父亲是因为要打印,名字肯定也是要打印的: 2.我们要知道每个结点的子树,删除结点会涉及调整: 3.我们要知道根节点,存放CEO. 所以我们的结点出来了,如下: struct Tman { string name; Tman *fat…

Building Fire Stations Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3820 Description Marjar University is a beautiful and peaceful place. There are N buildings and N - 1 bidirectional roads…

Fire Net Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 10   Accepted Submission(s) : 3 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Suppose that we have a square…

Fire   Description Country Z has N cities, which are numbered from 1 to N. Cities are connected by highways, and there is exact one path between two different cities. Recently country Z often caught fire, so the government decided to build some fireh…

算法指南白书 分别求一次人和火到达各个点的最短时间 #include<cstdio> #include<cstring> #include<queue> #include<algorithm> using namespace std; ; + ; + ; int R, C; char maze[maxr][maxc]; struct Cell { int r, c; Cell(int r, int c):r(r),c(c) {} }; ,,,}; ,,-,}…