SCU 4438 Censor|KMP变形题】的更多相关文章

传送门 Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text P. Her job is relatively simple -- just to find the first occurence of sensitive word w and remove it. frog repeats over and over again. Help her do the te…
 SCU 4438 Censor Time Limit:0MS     Memory Limit:0KB     64bit IO Format:%lld & %llu  Practice Description Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text pp. Her job is relatively simple -- just to find the…
题意:给定一个模式串和文本,要求删除所有模式串.可能删除后会形成新的模式串,必须全部删除. 思路1:kmp算法求得失配数组,用一个match数组记录文本串中第i字符和未删除的字符能匹配模式串的长度.这样每次删除字符串之后就不用再匹配,直接查询match数组即可.用栈模拟,自己实现的栈可以加快速度. AC代码 #include <cstdio> #include <cmath> #include <cctype> #include <bitset> #incl…
Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text \(p\). Her job is relatively simple -- just to find the first occurence of sensitive word \(w\) and remove it. frog repeats over and over again. Help her do th…
Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text p . Her job is relatively simple -- just to find the first occurence of sensitive word w and remove it. frog repeats over and over again. Help her do the tedio…
题意:找出字符串p中的w串删除,反复操作,直到找不到w,输出这个串 思路:哈希处理前缀和,如果值相同就删掉. 代码: #include<iostream> #include<algorithm> #include<cstdio> #include<stdio.h> #include<string.h> #include<queue> #include<cmath> #include<map> #include&…
frog is now a editor to censor so-called sensitive words (敏感词). She has a long text (p). Her job is relatively simple -- just to find the first occurence of sensitive word (w) and remove it. frog repeats over and over again. Help her do the tedious w…
4194: 字符串匹配 Time Limit: 1 Sec  Memory Limit: 128 MB Submit: 206  Solved: 78 Description 给你两个字符串A,B,请输出B字符串在A字符串中出现了几次. Input 多组测试数据,每组输入两个字符串.字符串的长度 <= 1000000. Output 输出B在A中出现的次数. Sample Input aaa aa Sample Output 1 HINT   Source WuYiqi #include <c…
题意: 给出一个母串和一个模式串求母串中最多能分成最大的子串数(每个字串中的各个数字的大小关系和模式串相同) 分析: KMP变形匹配规则变一下即可,用当前数字和下个数字的差表示,大小关系方便匹配 #include <map> #include <set> #include <list> #include <cmath> #include <queue> #include <stack> #include <cstdio>…
Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 27028    Accepted Submission(s): 11408 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…