Time past cannot be called back again. 时间不能倒流. Time tries all. 路遥知马力,日久见人心. Tit for tat is fair play. 人不犯我,我不犯人:人若犯我,我必犯人. To err is human. 人非圣贤,孰能无过. To know everything is to know nothing. 什么都知道,一如什么都不知道. To know oneself is true progress. 人贵…
http://stackoverflow.com/questions/11774868/svn-checkout-without-restoring up vote4down votefavorite 2 We have some company middleware and sometimes its difficult to find the correct version Im looking for so I often have to update to different versi…
Jurassic Remains Time Limit: 18000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu [Submit] [Go Back] [Status] Description Paleontologists in Siberia have recently found a number of fragments of Jurassic period dinosaur skeleton. The p…
今天在提交项目文件到本地SVN时提示错误如下: 过期:”global.php“在事务”21-1“, You have to update your working copy first. 运行update更新后再次提交又出现如下错误: svn: Commit failed (details follow):svn: Aborting commit: 'global.php' remains in conflict查了一下SVN的手册才知道原来是多个版本之间遇到冲突.此时你需要解决冲突(合并别人的…
Problem F: Polynomial Remains Given the polynomial a(x) = an xn + ... + a1 x + a0, compute the remainder r(x) when a(x) is divided by xk+1. The input consists of a number of cases. The first line of each case specifies the two integers n and k (0 ≤ n…
Jurassic Remains Paleontologists in Siberia have recently found a number of fragments of Jurassic period dinosaur skeleton. The paleontologists have decided to forward them to the paleontology museum. Unfortunately, the dinosaur was so huge, that the…
Jurassic Remains https://vjudge.net/problem/UVALive-2965 Paleontologists in Siberia have recently found a number of fragments of Jurassic period dinosaur skeleton. The paleontologists have decided to forward them to the paleontology museum. Unfortuna…
Basic remains Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 5221 Accepted: 2203 Description Given a base b and two non-negative base b integers p and m, compute p mod m and print the result as a base b integer. p mod m is defined as…
题目链接:http://poj.org/problem?id=2305 ime Limit: 1000MS Memory Limit: 65536K Total Submissions: 5326 Accepted: 2267 Description Given a base b and two non-negative base b integers p and m, compute p mod m and print the result as a base b integer. p…
题目大意:关于大数的mod和进制转换,直接使用Java的BigInteger类,正在copy式学习中... import java.io.*; import java.util.*; import java.math.*; class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); while (true) { int base = sc.nextInt(); if (bas…
