Romantic Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 2669 Description The Sky is Sprite. The Birds is Fly in the Sky. The Wind is Wonderful. Blew Throw the Trees Trees are Shaking, Leaves ar…

Romantic Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2835    Accepted Submission(s): 1117 Problem Description The Sky is Sprite.The Birds is Fly in the Sky.The Wind is Wonderful.Blew Throw t…

今天,我们将继续分享人类情感的系列文章.爱是人类最重要的感觉,也可能是各种形式的艺术(电影,音乐,书,画等)最常表达的主题 .这里有40个最美丽的爱的照片,将激励和给你一个全新的视觉角度为这种情绪.我们也非常乐意与你的朋友分享这篇文章. 您可能感兴趣的相关文章 好萌了!分享12幅可爱的婴儿照片 25幅记录欢乐瞬间的精美照片欣赏 分享20幅精美的秋季风景照片欣赏 30幅美得令人窒息的风景倒影照片 20幅精美绝伦光涂鸦摄影作品欣赏 Love is a place by Katsja Voronova…

The Romantic Hero Time Limit: 3000MS   Memory Limit: 131072KB   64bit IO Format: %I64d & %I64u Description 开头背景介绍无用 There is an old country and the king fell in love with a devil. The devil always asks the king to do some crazy things. Although the k…

2014多校4的1005 题目:http://acm.hdu.edu.cn/showproblem.php?pid=4901 The Romantic Hero Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 393    Accepted Submission(s): 150 Problem Description There i…

The Romantic Hero 题目链接: http://acm.hust.edu.cn/vjudge/contest/121349#problem/E Description There is an old country and the king fell in love with a devil. The devil always asks the king to do some crazy things. Although the king used to be wise and b…

Romantic Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3944    Accepted Submission(s): 1638 Problem Description The Sky is Sprite.The Birds is Fly in the Sky.The Wind is Wonderful.Blew Throw t…

题目大意:给你n个数字,然后分成两份,前边的一份里面的元素进行异或,后面的一份里面的元素进行与.分的时候依照给的先后数序取数,后面的里面的全部的元素的下标一定比前面的大.问你有多上种放元素的方法能够使得前面异或的值和后面与的值相等. dp[x][y] 表示走到第x步,得到y这个数字一共同拥有多少种方法. 可是须要注意这里得分一下,不能直接用dp数组存种数,你须要分一下从上一层过来的次数,和这一层自己能够到达的次数.然后取和的时候前后两个集合的种数进行乘法,注意边乘边取余. 顺便给一组数据: 4…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2669 Romantic Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4179    Accepted Submission(s): 1745 Problem Description The Sky is Sprite.The Birds…

Romantic Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3218 Accepted Submission(s): 1274 Problem Description The Sky is Sprite. The Birds is Fly in the Sky. The Wind is Wonderful. Blew Throw the…

35. Romantic Love and Ideal Romantic Relationship 爱情及理想爱情关系 ① Romantic love has clear evolutionary roots but our views about what makes an ideal romantic relationship can be swayed by the society we live in.So says psychologist Maureen O'Sullivan fro…

Romantic Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2385    Accepted Submission(s): 944 Problem Description The Sky is Sprite.The Birds is Fly in the Sky.The Wind is Wonderful.Blew Throw th…

The Romantic Hero Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1675    Accepted Submission(s): 705 Problem Description There is an old country and the king fell in love with a devil. The de…

Romantic Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6643    Accepted Submission(s): 2772 Problem Description The Sky is Sprite.The Birds is Fly in the Sky.The Wind is Wonderful.Blew Throw t…

Romantic Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8536    Accepted Submission(s): 3638 Problem Description The Sky is Sprite.The Birds is Fly in the Sky.The Wind is Wonderful.Blew Throw t…

DP....扫两次合并 The Romantic Hero Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 547    Accepted Submission(s): 217 Problem Description There is an old country and the king fell in love with a d…

裸的扩展欧几里德,求最小的X,X=((X0%b)+b)%b,每个X都对应一个Y,代入原式求解可得 #include<stdio.h> #include<string.h> typedef long long ll; ll ex_gcd(ll a,ll b,ll &x,ll &y){ if(!b){ x=,y=; return a; } int ans=ex_gcd(b,a%b,y,x); y-=a/b*x; return ans; } void cal(ll a,l…

题目 //第一眼看题目觉得好熟悉,但是还是没想起来//洪湖来写不出来去看了解题报告,发现是裸的 扩展欧几里得 - - /* //扩展欧几里得算法(求 ax+by=gcd )//返回d=gcd(a,b);和对应于等式ax+by=d中的x,y#define LL long longLL extend_gcd(LL a,LL b,LL &x,LL &y){ if(a==0&&b==0) return -1;//无最大公约数 if(b==0){x=1;y=0;return a;}…

题目链接 题意 :给你一个数列,让你从中挑选一些数组成集合S,挑另外一些数组成集合T,要求是S中的每一个数在原序列中的下标要小于T中每一个数在原序列中下标.S中所有数按位异或后的值要与T中所有的数按位与的值相同,问能找出多少符合要求的组合. 思路 :比赛的时候有点没有头绪,后来二师兄想出了状态转移方程,YN又改了很多细节,最后才A的.总之是个别扭的DP..... 一开始是 _xor[i][j^a[i]] += _xor[i-1][j] :j 的下一个状态 就是异或上a[i],这个数组所代表的意思…

题目链接 题意:给一个数组a,从中选择一些元素,构成两个数组s, t,使s数组里的所有元素异或 等于 t数组里的所有元素 位于,求有多少种构成方式.要求s数组里 的所有的元素的下标 小于 t数组里的所有的元素的下标. 分析:比赛的时候,刚开始脑子很乱,后来想了一下思路也敲了,发现自己的程序结果不对 自己一点一点计算后发现自己的程序有一部分计算重复了,其实还是dp的思路不够清晰. d[i][j]代表第i个数 新产生的结果为数字 j 的个数. AC代码: #include <iostream> #…

Problem Description There is an old country and the king fell in love with a devil. The devil always asks the king to do some crazy things. Although the king used to be wise and beloved by his people. Now he is just like a boy in love and can’t refus…

题目地址:HDU 4901 这题没想到最后竟然可以做出来.. .. 这题用了两次DP,先从前往后求一次异或的.再从后往前求一次与运算的. 各自是 1:求异或的时候,定义二维数组huo[1000][1024],前者指第几位,后者是哈希的思想.若huo[x][y]=2则表示最右边的数为第x位时,异或值为y的出现了两次,须要再定义一个hash数组.来保存前面出现的全部情况.再找有多少位的时候,用hash数组中出现的全部的值与当前的第x位的数字进行异或. 2:求与的时候,定义二维数组yu[1000][1…

题目链接 求最小割的值, 以及割边最少的情况的边数. 先求一遍最小割, 然后把所有割边的权值变为1, 其他边变成inf, 在求一遍最小割, 此时求出的就是最少边数. Inf打成inf  WA了好几发............ #include<bits/stdc++.h> using namespace std; #define pb(x) push_back(x) #define ll long long #define mk(x, y) make_pair(x, y) #define lso…

Now tell you two nonnegative integer a and b. Find the nonnegative integer X and integer Y to satisfy X*a + Y*b = 1. If no such answer print "sorry" instead. InputThe input contains multiple test cases.Each case two nonnegative integer a,b (0<…

Problem Description The Sky is Sprite.The Birds is Fly in the Sky.The Wind is Wonderful.Blew Throw the TreesTrees are Shaking, Leaves are Falling.Lovers Walk passing, and so are You. ................................Write in English class by yifenfei…

https://vjudge.net/problem/HDU-4901 题意 给n个数,构造两个集合,使第一个集合的异或和等于第二个集合的相与和,且要求第一个集合的元素下标都小于第二个集合的元素下标.问方案数 分析 dp来做.dp1[i][j]表示0~i的元素异或和为j的个数.dp2[i][j]表示i~n-1的元素相与和为j的个数.注意状态转移时要同时计算第i个数参与或不参与的情况,且dp1的第一维不能取到n-1,类似的,dp2的第一维不能取0.统计最终答案时需要合并,那么怎么才能防止重复呢?这…

The Sky is Sprite. The Birds is Fly in the Sky. The Wind is Wonderful. Blew Throw the Trees Trees are Shaking, Leaves are Falling. Lovers Walk passing, and so are You. ................................Write in English class by yifenfei Girls are cleve…

这道题对我来说有陷阱虽说是赤果果的扩展欧几里德,看样子基本攻还是不够哈,基本功夫一定要好,准备每天上那种洗脑课时分  多看看数论书,弥补一下 自己 狗一样的基础, 这道题用到了一个性质: 对于不定整数方程pa+qb=c,若 c mod Gcd(a, b)=0,则该方程存在整数解,否则不存在整数解. 上面已经列出找一个 整数解的方法,在找到p * a+q * b = Gcd(a, b)的一组解p0,q0后, /*p * a+q * b = Gcd(a, b)的其他整数解满足: p = p0 + a…

#include<iostream> #include<map> #include<string> #include<cstring> #include<cstdio> #include<cstdlib> #include<cmath> #include<queue> #include<vector> #include<algorithm> using namespace std; co…

求最小割及最小花费 把边权c = c*10000+1 然后跑一个最小割,则flow / 10000就是费用 flow%10000就是边数. 且是边数最少的情况.. #include<stdio.h> #include<string.h> #include<iostream> #include<math.h> #include<algorithm> #include<queue> #include<vector> using…