A. Arya and Bran time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies…

Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies. At first, Arya and Bran have 0 Candies. There are n days, at the i-th day, Arya finds ai candies in a box, that is given by…

Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies. At first, Arya and Bran have 0 Candies. There are n days, at the i-th day, Arya finds ai candies in a box, that is given by…

A. Arya and Bran time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies…

A. Arya and Bran time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies…

A. Arya and Bran time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies…

[Link]: [Description] [Solution] 傻逼题 [NumberOf WA] [Reviw] [Code] #include <bits/stdc++.h> using namespace std; #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define LL long long #define rep1(i,a,b) for (int i = a;i <= b;i++) #def…

题目链接:http://codeforces.com/contest/839 A. Arya and Bran 题意:每天给你一点糖果,如果大于8个,就只能给8个,剩下的可以存起来,小于8个就可以全部给完 解法:水题,按照题意模拟一下即可. #include <bits/stdc++.h> using namespace std; int n, k, a[110]; int main() { cin>>n>>k; int s = 0; for(int i=1; i<…

A. Arya and Bran time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies…

终于上蓝名了,hahahahaha,虽然这场的 B 题因为脑抽了,少考虑一种情况终判错了,还是很可惜的.. B题本来过来1500个人,终判之后只剩下了200多个,真的有毒!!!! A - Arya and Bran 题目大意:你需要k个糖果,你每天最多拿8个,有n天,每天提供你a[ i ]个糖果,如果糖果大于8个多出来的 可以储存下来,问你能不能在n天内拿到k个糖果. 思路:模拟就行了. #include<bits/stdc++.h> using namespace std; int n,k;…

一,用好 filter,map,和其它 ES6 新增的高阶遍历函数 二,理解和熟练使用 reduce 三,用递归代替循环(可以break!) 四,使用高阶函数遍历数组时可能遇到的陷阱 五,死磕到底,Transduce! 六,for 循环和 for … of 循环的区别 七,放弃倔强,实在需要用 for 循环了 Edit: 在我入职上一家公司的第一天,看到代码库里面一堆的 for 循环,内心有些崩溃,于是做了一次技术分享,展示怎样在代码中避免 for 循环.这篇文章是那次分享的总结.至于为什么我提…

A. Arya and Bran time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies…

It seemed as though he had been falling for years. Fly, a voice whispered in the darkness, but Bran did not know how to fly, so all he could do was fall. Maester Luwin made a little boy of clay, baked him till he was hard and brittle, dressed him in…

The hunt left at dawn. The king wanted wild boar at the feast tonight. Prince Joffrey rode with his father, so Robb had been allowed to join the hunters as well. Uncle Benjen, Jory, Theon Greyjoy, Ser Rodrik, and even the queen’s funny little brother…

Arya’s stitches were crooked again. She frowned down at them with dismay and glanced over to where her sister Sansa sat among the other girls. Sansa’s needlework was exquisite. Everyone said so. “Sansa’s work is as pretty as she is,” Septa Mordane to…

The morning had dawned clear and cold, with a crispness(易碎:清新) that hinted(暗示:示意) at the end of summer. They set forth at daybreak to see a man beheaded(砍头), twenty in all, and Bran rode among them, nervous with excitement. This was the first time he…

1.github中的项目clone到本地(路径在最后),然后将arya文件夹复制到你的django工程中作为一个独立的app,该app实现了RBAC(基于角色的权限访问控制Role-Based Access Control)和CRM(客户关系管理). 完成效果: 2.setting中注册arya和配置rbac相关设置 INSTALLED_APPS = [ ..... 'arya.apps.AryaConfig', ] .... # ############################## R…

准备工作   内核开发是编写代码以及调试各种系统组件的漫长过程.一开始这似乎是一个让人畏惧的任务,但是并不需要大量的工具集来编写自己的内核.这个内核开发教程主要涉及使用GRUB将内核加载到内存中.GRUB需要被定向到受保护的二进制镜像中,这个镜像就是我们将要构建的内核.   使用本教程,你至少需要具备C语言基础,并且强烈推荐了解x86汇编知识,它允许你操作处理器中特定的寄存器.所以你至少需要一个可以生成32位编码的编译器,一个32位的链接器和一个能生成32位x86的汇编器.   对于硬件,你必须…

介绍   内核开发不是件容易的事,这是对一个程序员编程能力的考验.开发内核其实就是开发一个能够与硬件交互和管理硬件的软件.内核也是一个操作系统的核心,是管理硬件资源的逻辑.   处理器或是CPU是内核需要管理的最重要的系统资源之一.内核对其的管理体现在:给特定操作分配时间,并允许在另一个调度事件发生时中断任务或进程.也就是多任务处理(multitasking).多任务处理的实现方式有: 协作式多任务处理(cooperative multitasking):当程序自身想要放弃处理下一个可执行进程或…

http://www.cnblogs.com/liloke/archive/2011/12/21/2296004.html 最近在看<orange’s>一书,有点想自己写一个轻量级OS的想法,设计和架构上会参照orang’s和Linux 0.11 kernel. 这个网站,上面的资料对于我这样的新手无疑是一份宝贵的财富啊.它详细介绍了内核程序必不可少的几大模块,并且对于每一个模块都有一些代码示例.看着文章代码,边做边学,真是一件愉快的事情 本来还想翻译成中文献给大家,不过google了一下,已…

全局描述符表(GDT)   在386平台各种保护措施中最重要的就是全局描述符表(GDT).GDT为内存的某些部分定义了基本的访问权限.我们可以使用GDT中的一个索引来生成段冲突异常, 让内核终止执行异常的进程.现代操作系统大多使用"分页"的内存模式来实现该功能, 它更具通用性和灵活性.GDT还定义了内存中的的某个部分是可执行程序还是实际的数据.GDT还可定义任务状态段(TSS).TSS一般在基于硬件的多任务处理中使用, 所以我们在此并不做讨论.需要注意的是TSS并不是启用多任务的唯一方…

打印到屏幕   现在, 我们需要尝试打印到屏幕上.为此, 我们需要管理屏幕滚动, 如果能允许使用不同的颜色就更好了.好在VGA视频卡为我们提供了一片内存空间, 允许同时写入属性字节和字符字节对, 可以更简单地在屏幕上显示信息.VGA控制器负责自动绘制屏幕上的更新.屏幕滚动由内核软件来管理.从技术上讲, 这将是我们写的第一个驱动程序.   如上所述, 文本空间只是我们地址空间的一块存储区域, 这片缓冲区位于物理内存的0xB800地址, 缓冲区的数据类型为"short"类型, 这意味着这片…

目录 创建main函数和链接C文件 PS: 下面是我自己写的 Win10安装gcc编译器 本节教程对应的Linux下的编译脚本 _main的问题 创建main函数和链接C文件   一般C语言使用main()函数作为程序的入口点, 为了符合我们平时的编程习惯, 这里我们也使用main()函数作为C代码的入口点, 并在"start.asm"文件中添加中断服务程序来调用C函数.   在这一节教程,我们将尝试创建一个"main.c"文件和一个包含常用函数原型的头文件&quo…

目录 内核初步 内核入口 链接脚本 汇编和链接 PS: 下面是我自己写的 64位Linux下的编译脚本 内核初步   在这节教程, 我们将深入研究一些汇编程序, 学习创建链接脚本的基础知识以及使用它的原因.最后, 我们将学习如何使用batch(批处理)文件自动汇编.编译和链接这个最基本的受保护模式下的内核.本教程假定你已经安装了NASM和GCC, 并且了解一点点x86汇编语言. 内核入口   内核的入口点是当引导程序(bootloader)调用内核时最先执行的代码段.这段代码一直以来几乎都是使用…

中断描述符表(IDT)   中断描述符表(IDT)用于告诉处理器调用哪个中断服务程序(ISR)来处理异常或汇编中的"int"指令.每当设备完成请求并需要服务事, 中断请求也会调用IDT条目.异常和ISR将在下一节进行详细的说明.   每一项IDT都与GDT相似, 两者都有一个基地址, 一个访问标志, 而且都长64bits.这两类描述符表最主要的区别在于这些字段的含义: 在IDT中的基地址是中断时应调用的ISR的地址.IDT也没有边界(limit), 而是需要一个指定的段, 该段与给定的…

中断服务程序(ISR)   中断服务程序(ISR)用于保存当前处理器的状态, 并在调用内核的C级中断处理程序之前正确设置内核模式所需的段寄存器.而工作只需要15到20行汇编代码来处理, 包括调用C中的处理程序.我们还需要将IDT条目指向正确的ISR以正确处理异常.   异常是导致处理器无法正常执行的特殊情况, 比如除以0结果是未知数或者非实数, 因此处理器会抛出异常, 这样内核就可以阻止进程或任务引起任何问题.如果处理器发现程序正尝试访问不允许其访问的内存, 则会引起一般保护错误.当你设置内存页…

Eddard Stark rode through the towering bronze doors of the Red Keep sore, tired, hungry, and irritable. He was still ahorse, dreaming of a long hot soak(浸:湿透:), a roast fowl, and a featherbed, when the king’s steward(管家:乘务员) told him that Grand Maest…

The courtyard rang to the song of swords. Under black wool, boiled leather, and mail, sweat trickled icily down Jon’s chest as he pressed the attack. Grenn stumbled backward, defending himself clumsily. When he raised his sword, Jon went underneath i…

Jon climbed the steps slowly, trying not to think that this might be the last time ever. Ghost padded silently beside him. Outside, snow swirled through the castle gates, and the yard was all noise and chaos, but inside the thick stone walls it was s…

Of all the rooms in Winterfell’s Great Keep, Catelyn’s bedchambers(['bedtʃeɪmbə]卧室,寝室) were the hottest. She seldom had to light a fire. The castle had been built over natural hot springs, and the scalding(['skɔːldɪŋ]滚烫的:尖刻的) waters rushed through it…