Geeks LCA最低公共单亲节点

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Geeks LCA最低公共单亲节点

给出一颗二叉树.找到两个值的最小公共节点. 假设两个值都会在树中出现. 假设可能不会出现的话,也非常easy.就查找一遍看两个值是否在树中就能够了.假设不在就直接返回NULL. 基本思想:就是在二叉树中比較节点值和两个值的大小,假设都在一边(左边或者右边)那么就往下继续查找,否则就是都在同一边了,那么就能够返回这个节点了,这个节点就是最低公共单亲节点了. 參考:http://www.geeksforgeeks.org/lowest-common-ancestor-in-a-binary-sear…

LCA最小公共父节点的解题思路

LCA最小公共父节点解法: 1.二叉搜索树: 中序遍历是升序,前序遍历即按序插入建树的序列. 二叉搜索树建树最好用前序+中序,如果用前序建树,最坏情况会退化为线性表,超时. 最近公共祖先甲级: A1143,1151 利用二叉搜索树的性质寻找结点u和v的最低公共祖先(递归解法) 1)如果根结点的值大于max(u,v),说明u和v均在根结点的左子树,则进入根结点的左子结点继续递归 2)如果根结点的值小于min(u,v),说明u和v均在根结点的右子树,则进入根结点的右子结点继续递归 3)剩下的情况就是…

剑指Offer（第二版）面试案例：树中两个节点的最低公共祖先节点

(尊重劳动成果,转载请注明出处:http://blog.csdn.net/qq_25827845/article/details/74612786冷血之心的博客) 剑指Offer(第二版)面试案例:树中两个节点的最低公共祖先节点题目:输入两个树节点,求它们的最低公共祖先节点. 反问:这棵树是不是二叉树? 面试官:是二叉树,并且是二叉搜索树. 思路: 二叉搜索树是经过排序的,位于左子树的节点都比父节点小,位于右子树的节点都比父节点大.既然要找最低的公共祖先节点,我们可以从根节点开始进行比较. 若…

235. Lowest Common Ancestor of a Binary Search Tree(LCA最低公共祖先)

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that ha…

[leetcode]236. Lowest Common Ancestor of a Binary Tree 二叉树最低公共父节点

Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q…

LeetCode 236 Lowest Common Ancestor of a Binary Tree 二叉树两个子节点的最低公共父节点

/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* lowestCommonAncestor(TreeNode* root, TreeNo…