1075 PAT Judge (25 分) The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each…

1075 PAT Judge (25分)   The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For eac…

题目地址:http://pat.zju.edu.cn/contests/pat-a-practise/1075 此题主要考察细节的处理,和对于题目要求的正确理解,另外就是相同的总分相同的排名的处理一定要熟练,还有就是编译没有通过为零分,没有提交显示为"-": #include <cstdio> #include <vector> #include <algorithm> using namespace std; ; vector<); int…

题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805393241260032 题意: 有m次OJ提交记录,总共有k道题,n个人.每道题有一个最高分. 现在要统计用户的排名,如果总分相同,完整AC的题目数高的排前面,都一样id小的排前面. 如果没有提交记录,或者提交记录都是-1的用户,就不输出. 思路: 根据题意模拟.PAT的题目都要耐心好好读题啊,各种情况都要看清楚. #include<cstdio> #inc…

The ranklist of PAT is generated from the status list, which shows the scores of the submittions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line…

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line…

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line…

排序题 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include <map> using namespace std; const int N = 100005; int score[10]; struct Node { int id; int problem; int get; }person[N]; struct ANS {…

简单模拟题. 注意一点:如果一个人所有提交的代码都没编译通过,那么这个人不计排名. 如果一个人提交过的代码中有编译不通过的,也有通过的,那么那份编译不通过的记为0分. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<str…

相当于是模拟OJ评测,这里注意最后输出:1.那些所有提交结果都是-1的(即均未通过编译器的),或者从没有一次提交过的用户,不需要输出.2.提交结果为-1的题目,最后输出分数是03.某个题目从没有提交过的,输出'-' #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <queue>…