目录 题目链接 注意点 解法 小结 题目链接 Word Ladder - LeetCode 注意点 每一个变化的字母都要在wordList中 解法 解法一:bfs.类似走迷宫,有26个方向(即26个字母),起点是beginWord,终点是endWord.每一次清空完队列ret+1表示走了一步.bfs可以保证是最短路径. class Solution { public: int ladderLength(string beginWord, string endWord, vector<string…

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start…

题目: Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:…

Given two words (beginWord and endWord), and a dictionary, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For exam…

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given: start = "hi…

其他LeetCode题目欢迎访问:LeetCode结题报告索引 LeetCode:Word Ladder Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word…

Problem Link: http://oj.leetcode.com/problems/word-ladder-ii/ Basically, this problem is same to Word Ladder I, which uses a double-direction BFS. However, the difference is that we need to keep track of all paths during the double-direction BFS in o…

[leetcode]Word Ladder II @ Python 原题地址:http://oj.leetcode.com/problems/word-ladder-ii/ 参考文献:http://blog.csdn.net/doc_sgl/article/details/13341405   http://chaoren.is-programmer.com/ 题意:给定start单词,end单词,以及一个dict字典.要求找出start到end的所有最短路径,路径上的每个单词都要出现在dict…

Word Ladder II 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/word-ladder-ii/description/ Description Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such…

Word Ladder题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/word-ladder/description/ Description Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such…

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start = "hit…

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time    Each intermediate word must exist in the dictionary For example, Given:start = "…

Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list. Note…

Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list. Note…

Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…

Leetcode之广度优先搜索(BFS)专题-127. 单词接龙(Word Ladder) BFS入门详解:Leetcode之广度优先搜索(BFS)专题-429. N叉树的层序遍历(N-ary Tree Level Order Traversal) 相同思路的题目:Leetcode之广度优先搜索(BFS)专题-752. 打开转盘锁(Open the Lock) 给定两个单词(beginWord 和 endWord)和一个字典,找到从 beginWord 到 endWord 的最短转换序列的长度.…

题目: Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list.…

Word Ladder Total Accepted: 24823 Total Submissions: 135014My Submissions Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Ea…

  Word Ladder II Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, G…

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start = "hit…

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start…

原题地址 BFS Word Ladder II的简化版(参见这篇文章) 由于只需要计算步数,所以简单许多. 代码: int ladderLength(string start, string end, unordered_set<string> &dict) { if (start == end) ; unordered_set<string> old; queue<string> layer; ; layer.push(start); while (!laye…

Problem: Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:sta…

Word Ladder II Total Accepted: 11755 Total Submissions: 102776My Submissions Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each i…

Word Ladder Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example,…

Word Ladder II Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a timeEach intermediate word must exist in the dictionaryFor example, Given…

[题目] Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start =…

1. Convert Sorted List to Binary Search Tree Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth…

题意:给出两个单词,以及一个set集合,当中是很多的单词.unordered_set是无序的集合,也就是说找的序列也是无序的了,是C++11的标准,可能得升级你的编译器版本了.要求找出一个从start到end这两个单词的变换序列.从start开始,每次可以变一个字母,且所变之后的单词必须在set中,最后要求变成end,问经过了多少个中间变换?注意要加多2次(start和end也要算),这是规定. 思路:广度搜索,以start为树根,一层一层扩展,直到找到end,返回数的深度即可.步骤是这样的,先…

127. Word Ladder 这道题使用bfs来解决,每次将满足要求的变换单词加入队列中. wordSet用来记录当前词典中的单词,做一个单词变换生成一个新单词,都需要判断这个单词是否在词典中,不在词典中就不能加入队列. pathCnt用来记录遍历到的某一个词使用的次数,做一个单词变换生成一个新单词,都需要判断这个单词是否在pathCnt中,如果在,则说明之前已经达到过,这次不用再计算了,因为这次计算的path肯定比之前多.pathCnt相当于剪枝. class Solution { pub…