E. Polish Fortress time limit per test 2.0 s memory limit per test 256 MB input standard input output standard output The Malbork castle is the largest brick castle in the world. It was built in 1274 in honor to Holy Mary, and is located near the riv…

F. Auction of Services time limit per test 2.0 s memory limit per test 256 MB input standard input output standard output It is becoming more common to use strategies based on social networks for shopping, contract services, arrange meetings, etc. Su…

题意:你从开始坐标到末尾坐标,要经过 k 秒,然后给你每秒的风向,和飞机的最大速度,问能不能从开始到末尾. 析:首先这个风向是不确定的,所以我们先排除风向的影响,然后算出,静风是的最小速度,如果这都大于最大速度,肯定是不可能,如果可能, 再计算出每秒走的单位长度,然后再模拟整个过程. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <str…

BUPT2017 wintertraining(15) #4F Gym - 101124A 题意 给定画框宽度,画的四边和一个对角线长度,求画框外沿周长. 题解 过顶点做画框的垂线,每个角都得到两个全等直角三角形.然后用余弦公式求得四个角,再在直角三角形中计算出比内沿多出来的长度,加上画的四边长度即可. 代码 #include <cstdio> #include <cstring> #include <algorithm> #include <cmath>…

http://codeforces.com/gym/101147/problem/I I. On the way to the park time limit per test 5 seconds memory limit per test 64 megabytes input walk.in output standard output Engineers around the world share a lot of common characteristics. For example,…

pro:给定规则的多边形,规则是指顶点都在整点上,而且是相互垂直的边的交点. 现在给定两个多边形A,B,问A,B缩小,旋转后是否可以变为同一个图形. sol:缩小的话,直接离散化即可,就可以去掉没用的部分,旋转的话,可以手动旋转4次. #include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<=b;i++) using namespace std; ; struct in{ int N,a[maxn],b[maxn],x[maxn]…

精度有点毒, 其实可以不用double, 因为A, B必定在其中一个在三角形上,可以投影到只有x,y轴的地方叉积比较. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PII pair<int, int> #define PLI pair<LL, int> #define PLL pair<LL,…

题目链接:https://cn.vjudge.net/contest/275150#problem/D 题目大意: 问你能满足那个矩形可以顺利通过的条件,然后求出最小的w 具体思路:首先,我们应该将情况分成两种． 第一种,这个矩形可以完全的放在弯道中,这是第一种情况, 第二种,这个矩形不能完全放在弯道中,也就是说当上面都已经到达出去弯道的边界了,然而下面还没有完全的进来,这是第二种情况． AC代码: #include<iostream> #include<cstring> #inc…

题意:给定几个圆,求最短的围合,把这几个包围起来,而且到圆的距离都不小于10. 思路:把每个圆的半径+10,边等分5000份,然后求凸包即可. #include<bits/stdc++.h> using namespace std; #define mp make_pair typedef long long ll; const double inf=1e200; ; *atan(1.0); :(x<?-:);} struct point{ double x,y; point(,):x(…

Identity Checker 题目连接: http://codeforces.com/gym/100015/attachments Description You likely have seen that x(sin x +cos2 x) ! x = 0, and you may have seen that sin(2x) ! 2 sin x cos x =0. But did you know that tan (2x)(x ! x tan2 x) ! 2x tan x = 0? Wo…

之前几乎没写过什么这种几何的计算题.在众多大佬的博客下终于记起来了当时的公式.嘚赶快补计算几何和概率论的坑了... 这题的要求,在对两圆相交的板子略做修改后,很容易实现.这里直接给出代码.重点的部分有:两圆在相离(或外交)时输出第一个圆的面积.内涵(或内切)则需要分类讨论,是羊的圈大.还是狼的圈大.以下是代码: #include<iostream> #include<cmath> #include<stdio.h> using namespace std; int ma…

题目链接:http://codeforces.com/gym/101149/problem/K 题目大意: 给你两个点a,b.一个人在a点,一个人在b点,b点的人要追杀a的点,他的跑步速度是a的两倍.如果a点的人能在b点追击到之前回到a点这个位置,那么这个人就是安全的(b点的人追击a点的人的追击方案是:一直朝着a点的人所在的位置奔跑过去).问,这个人的安全区域是多少? 思路:几何果然不会= =,连sb题都没想到 因为是面积,所以说两点之间的距离就决定了最后的结果.因为题目给出的是单位面积.所以对…

一.有关球体SphereGeometry构造函数参数说明 <1>.SphereGeometry(radius, widthSegments, heightSegments, phiStart, phiLength, thetaStart, thetaLength) radius - sphere radius. Default is 50. 球体半径 默认值 50 widthSegments - number of horizontal segments. Minimum value is 3…

Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, *, /. Each operand may be an integer or another expression. Some examples: ["2", "1", "+", "3", "*"] -&g…

原文 Some fresh air After your time underground,you can return to ground level or maybe even a little higher at Kosciuszko Mound. The 34-meter hill is a memorial for a Polish military hero but also offers a panoramic view of surrounding city from top.…

原文 History lives on in this distinguished Polish city Though it may be ancient. KraKow, Poland, is alive and well as it celebrates and commemorates its meaningful history. Looking up When scaning the skies of Krakow,most agree that Wawel Castle cast…

 Gym 101047M Removing coins in Kem Kadrãn Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Practice Description standard input/output Andréh and his friend Andréas are board-game aficionados. They know many of their friend…

 Gym 101047K Training with Phuket's larvae Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Practice Description standard input/output Thai cuisine is known for combining seasonings so that every dish has flavors that are…

Gym 101047E Escape from Ayutthaya Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u  Practice  Description standard input/output Ayutthaya was one of the first kingdoms in Thailand, spanning since its foundation in 1350 to…

 Gym 101047B  Renzo and the palindromic decoration Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Practice Description standard input/output At the ruins of Wat Phra Si Sanphet (วดพระศรสรรเพชญ), one can find famous inscr…

Evaluate Reverse Polish Notation 题目描述: Evaluate the value of an arithmetic expression in Reverse Polish Notation.Valid operators are +, -, , /. Each operand may be an integer or another expression.Some examples:["2", "1", "+"…

关于几何服务 几何服务用于辅助应用程序执行各种几何计算,如缓冲区.简化.面积和长度计算以及投影.在 ArcGIS Server 管理器中启动几何服务之后,您才能够在应用程序开发过程中使用该服务. 问题及解决方案大致描述: 在使用几何服务的cut功能时出现错误.对于某些线要素(如,可供测试的修改前的要素)无法裁剪.后经测试找到问题原因,修改后的线要素. 如图,弯弯曲曲的线要素为裁剪目标(Target Geometries),直线要素为裁剪(Cutter).箭头所指为问题所在. 如下两图将 裁剪目标…

几何服务,cut功能测试,输入要素target(修改后)内容. {"displayFieldName":"","fieldAliases":{"FID":"FID","Id":"Id","Shape_Length":"Shape_Length"},"geometryType":"esriGeomet…

几何服务,cut功能测试,输入要素target(修改前)内容. {"geometryType":"esriGeometryPolyline","geometries":[{"paths":[[[12449108.967500001,3975003.0829000026],[12448956.5808,3975263.951899998],[12448888.1684,3975553.0798999965],[12449105.…

有时候需要编辑一些几何图形,如三角形,圆锥曲线等,在UWP应用中加入这些几何作图功能是件费时间又很难做好的事.其实Windows 10 应用商店中已有一些专业的几何作图工具了,那么能借来一用吗?答案是肯定的. UWP中,微软为Windows.System.Launcher启动器新增了很多的功能,以前只能启动App,打开指定扩展名文件,对uri协议的解析,以及当启动的应用没有安装时则会提示前往商店下载等. 如今,微软丰富了Launcher的功能,通过新增的LaunchUriForResultsAs…

/* 最小生成树 + 几何判断 Kruskal 球心之间的距离 - 两个球的半径 < 0 则说明是覆盖的!此时的距离按照0计算 */ #include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; ]; struct ball{ double x, y, z, r; }; struct…

题目链接 http://codeforces.com/gym/101102/problem/J Description standard input/output You are given an array A of integers of size N, and Q queries. For each query, you will be given a set of distinct integers S and two integers L and R that represent a…

题目链接 http://codeforces.com/gym/100917/problem/J Description standard input/outputStatements The jury of Berland regional olympiad in informatics does not trust to contest management systems, so the Berland regional programming contest is judged by th…

题目链接 http://codeforces.com/gym/100917/problem/D problem description Famous Berland coder and IT manager Linus Gates announced his next proprietary open-source system "Winux 10.04 LTS" In this system command "dir -C" prints list of all…

题目链接 http://codeforces.com/gym/101102/problem/D problem  description Given an R×C grid with each cell containing an integer, find the number of subrectangles in this grid that contain only one distinct integer; this means every cell in a subrectangle…