问题描述 给一组数,判断这组数中是否含有132 pattern. 132 pattern: i < j < k, 且 ai < ak < aj 第一种解法 使用栈来保存候选的子区间,不断地判断新元素是否落在栈顶的区间内,这其中需要一些判断. class Solution { public: bool find132pattern(vector<int>& nums) { int n = nums.size(); stack<pair<int,int&…
对一个三个元素以上的数组,如果存在1-3-2模式的组合,则返回true. 1-3-2模式就是值的排序是i<k<j但是下标排序是i<j<k. 解法一: 硬解,利用一个变量存储是否找到了较大值和较小值,因为是1-3-2,所以从后往前遍历才能找到较当前值更大和更小的值. Runtime: 648 ms, faster than 12.76% of C++ online submissions for 132 Pattern. class Solution { public: bool f…
[LeetCode]456. 132 Pattern 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/132-pattern/description/ 题目描述: Given a sequence of n integers a1, a2, -, an, a 132 pattern is a subs…
456. 132 Pattern Given an array of integers a1, a2, a3-an, judge if there exists the 132 pattern. 132 pattern is ai < ak < aj, in which i < j < k. Solution: refer: https://discuss.leetcode.com/topic/67881/single-pass-c-o-n-space-and-time-solut…
Given a sequence of n integers a1, a2, ..., an, a 132 pattern is a subsequence ai, aj, ak such that i < j < k and ai < ak < aj. Design an algorithm that takes a list of n numbers as input and checks whether there is a 132 pattern in the list.…
Given a sequence of n integers a1, a2, ..., an, a 132 pattern is a subsequence ai, aj, ak such that i < j < k and ai < ak < aj. Design an algorithm that takes a list of n numbers as input and checks whether there is a 132 pattern in the list.…
