Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 在LeetCo…
9.6 Implement an algorithm to print all valid (e.g., properly opened and closed) combinations of n-pairs of parentheses.EXAMPLEInput: 3Output: ((())), (()()), (())(), ()(()), ()()() LeetCode上的原题,请参见我之前的博客Generate Parentheses 生成括号. 解法一: class Solution…
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 给定一…
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. Have you met this question in a real interview?     Example Given n = 3, a solution set is: "((()))", "(()())", "(())()",…
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]   …
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 题意:…
给 n 对括号,写一个函数生成所有合适的括号组合.比如,给定 n = 3,一个结果为:[  "((()))",  "(()())",  "(())()",  "()(())",  "()()()"]详见:https://leetcode.com/problems/generate-parentheses/description/ 由于字符串只有左括号和右括号两种字符,而且最终结果必定是左括号3个,右括号3个…
题意: 产生n对合法括号的所有组合,用vector<string>返回. 思路: 递归和迭代都可以产生.复杂度都可以为O(2n*合法的括号组合数),即每次产生出的括号序列都保证是合法的. 方法都是差不多的,就是记录当前产生的串中含有左括号的个数cnt,如果出现右括号,就将cnt--.当长度为2*n的串的cnt为0时,就是答案了,如果当前cnt比剩下未填的位数要小,则可以继续装“(”,否则不能再装.如果当前cnt>0,那么就能继续装“)”与其前面的左括号匹配(无需要管匹配到谁,总之能匹配)…
题目 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n=3, a solution set is:  [   "( ( ( ) ) )",   "( ( ) ( ) )",   "( ( ) ) ( )",   "( ) ( ( ) )&q…
Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]"…