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Box of Bricks Time Limit: 2 Seconds      Memory Limit: 65536 KB Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. ``Look, I've built a wall!'', he tells his older sister Alice.…
这道题简单的翻译成纯数学语言就是给你n个数字,每次运算只能是加1或者减1,问经过最短几步可以使得n个数字相等 由于题目限定了n个数字一定有平均数,所以求出avg,将所有比其大的数字或者比其小的数字的差加起来就是步数 见代码: #include <stdio.h> int main() { ],s=; while(scanf("%d",&n)!=EOF&&n) { ,avg,result=; ;i<n;i++) { scanf("%d&…
Box of Bricks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5994    Accepted Submission(s): 2599 Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one up…
Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. “Look, I've built a wall!”, he tells his older sister Alice. “Nah, you should make all stacks the same height. The…
Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 19503   Accepted: 7871 Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. "Look, I've built a wall!"…
Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. "Look, I've built a wall!", he tells his older sister Alice. "Nah, you should make all stacks th…
Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. Look, I've built a wall!'', he tells his older sister Alice.Nah, you should make all stacks the same heigh…
 Box of Bricks  Little Bob likes playing with his box of bricks. He puts the bricks one upon another and buildsstacks of different height. ``Look, I've built a wall!'', he tells his older sister Alice. ``Nah, you shouldmake all stacks the same height…
Box of Bricks Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 63   Accepted Submission(s) : 20 Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one upon ano…
http://acm.hdu.edu.cn/showproblem.php?pid=2088 Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. “Look, I've built a wall!”, he tells his older sister Alice…
传送门: http://acm.hdu.edu.cn/showproblem.php?pid=2088 Box of Bricks Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 20219    Accepted Submission(s): 6473 Problem Description Little Bob likes playi…
Box of Bricks Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 19949   Accepted: 8029 Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. "Look, I've buil…
本文索引目录: 一.贪心算法的基本思想以及个人理解 二.汽车加油问题的贪心选择性质 三.一道贪心算法题点拨升华贪心思想 四.结对编程情况 一.贪心算法的基本思想以及个人理解: 1.1 基本概念: 首先我们从课本中仔细品读基本的贪心概念,顾名思义,贪心算法总是作出在当前看来最好的选择.也就是说贪心算法并不从整体最优考虑,它所作出的选择只是在某种意义上的局部最优选择.当然,希望贪心算法得到的最终结果也是整体最优的.虽然贪心算法不能对所有问题都得到整体最优解,但对许多问题它能产生整体最优解.如单源最短…
描述 Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. "Look, I've built a wall!", he tells his older sister Alice. "Nah, you should make all stacks the same height. Th…
Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. ``Look, I've built a wall!'', he tells his older sister Alice. ``Nah, you should make all stacks the same height. Then you wou…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1326 题目大意: 给n堵墙,每个墙的高度不同,求最少移动多少块转使得墙的的高度相同. 解题思路: 找到平均墙的高度(即最后墙的高度),遍历所有墙,如果小于平均墙,则用平均墙减去高度即是要移动的高度,统计所有需要"补"的高度即可.注意输出. AC Code: #include<bits/stdc++.h> using namespace std; int main() { ; w…
Tips:先求出平均数再分别计算各数与平均数的差相加,注意两个测试结果之间要空一行 #include<iostream> using namespace std; int main() { ; while(cin>>T) { ) { ; } count ++; ,totalsum=,avg=; ;i<T;i++) { cin>>b[i]; sum += b[i]; } avg = sum/T; ;i<T;i++) { if(b[i]>avg) { to…
http://www.bnuoj.com/bnuoj/problem_show.php?pid=1596 这个题一开始以为要求最少移动次数,把我吓到了,原来只要求最少移动几个方块就行了..这一下就变简单很多了.. AC代码: #include<iostream> #include<cstdio> #include<algorithm> using namespace std; bool cmp(int a, int b) { return a<b; } int m…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2088 解题思路:一堆高度不同的砖块,需要把它们砌成一堵墙,即每一堆砖的高度相同(即砖的总数除以砖的堆数,即砖的平均值),然后砖的数目比平均数大的需要搬砖给砖的数目比平均数少的,最后把它们加起来就可以了. 反思:PE了两次,因为题目中说的是每一组测试数据之间要空一行,读题要仔细. #include<stdio.h> int main() { int n,a[60]; int i,flag=0; wh…
acm之pku题目分类 对ACM有兴趣的同学们可以看看 DP:  1011   NTA                 简单题  1013   Great Equipment     简单题  1024   Calendar Game       简单题  1027   Human Gene Functions   简单题  1037   Gridland            简单题  1052   Algernon s Noxious Emissions 简单题  1409   Commun…
以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…
杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze 广度搜索1006 Redraiment猜想 数论:容斥定理1007 童年生活二三事 递推题1008 University 简单hash1009 目标柏林 简单模拟题1010 Rails 模拟题(堆栈)1011 Box of Bricks 简单题1012 IMMEDIATE DECODABILITY…
各种杂题,水题,模拟,包括简单数论. 1001 A+B 1002 A+B+C 1009 Fat Cat 1010 The Angle 1011 Unix ls 1012 Decoding Task 1019 Grandpa's Other Estate 1034 Simple Arithmetics 1036 Complete the sequence! 1043 Maya Calendar 1054 Game Prediction 1057 Mileage Bank 1067 Rails 10…
2992.357000 1000 A+B Problem1214.840000 1002 487-32791070.603000 1004 Financial Management880.192000 1003 Hangover792.762000 1001 Exponentiation752.486000 1006 Biorhythms705.902000 1005 I Think I Need a Houseboat686.540000 1011 Sticks647.566000 1007…
转载:from http://blog.csdn.net/qq_28236309/article/details/47818349 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029. 1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093. 1094.1095.1096.1097.1098.1106.1108.1157.116…
题号:a001: 哈囉 背景知识:输出语句,while not eof 题号:a002: 簡易加法 背景知识:输出语句,while not eof,加法运算 题号:a003: 兩光法師占卜術 背景知识:while not eof,分支语句,求余 PS:%表示求余 题号:a004: 文文的求婚 背景知识:while not eof,分支语句,判断闰年 题号:a005: Eva 的回家作業 背景知识:循环,if语句,等比数列,等差数列,输出语句 题号:a006: 一元二次方程式 背景知识:if语句的…
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http://vjudge.net/vjudge/contest/view.action?cid=54562#overview H  B. Polygons http://codeforces.com/problemset/problem/166/B 目前已知两种解法,先贴一个凸包的.算法是把两个多边形的点一起做一个凸包,看这个凸包是否包含b的点,包含说明b不是严格在a内,凸包要包括边上的点.复杂度nlogn,n为两个凸包点的和n=m+n=120000.nlogn=2024720. #inclu…
Box of Bricks Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14836    Accepted Submission(s): 4912 Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one up…
Hot~~招聘——巴卡斯(杭州),亚信科技,壹晨仟阳(杭州) Box of Bricks Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14836    Accepted Submission(s): 4912 Problem Description Little Bob likes playing with his box of br…