A positive integer is magical if it is divisible by either A or B. Return the N-th magical number.  Since the answer may be very large, return it modulo 10^9 + 7. Example 1: Input: N = 1, A = 2, B = 3 Output: 2 Example 2: Input: N = 4, A = 2, B = 3 O…

A positive integer is magical if it is divisible by either A or B. Return the N-th magical number.  Since the answer may be very large, return it modulo 10^9 + 7. Example 1: Input: N = 1, A = 2, B = 3 Output: 2 Example 2: Input: N = 4, A = 2, B = 3 O…

题目如下: 解题思路:本题求的是第N个Magical Number,我们可以很轻松的知道这个数的取值范围 [min(A,B), N*max(A,B)].对于知道上下界求具体数字的题目,可以考虑用二分查找.这样题目就从找出第N个Magical Number变成判断一个数是否是第N个Magical Number.假设n是其中一个Magical Number,显然n满足 n % A == 0 或者 n % B == 0.对于A来说,从A到n之间有n/A个Magical Number,而对B来说是n/B…

A positive integer is magical if it is divisible by either A or B. Return the N-th magical number.  Since the answer may be very large, return it modulo 10^9 + 7. Example 1: Input: N = 1, A = 2, B = 3 Output: 2 Example 2: Input: N = 4, A = 2, B = 3 O…

根据CC150的解决方式和Introduction to Java programming总结: 使用了两种方式,递归和迭代 CC150提供的代码比较简洁,不过某些细节需要分析. 现在直接运行代码,输入n(其中用number代替,以免和方法中的n混淆)的值,可以得出斐波那契数. 代码如下: /* CC150 8.1 Write a method to generate the nth Fibonacci number Author : Mengyang Rao note : Use two me…

problem 1137. N-th Tribonacci Number solution: class Solution { public: int tribonacci(int n) { ) ; || n==) ; , t1 = , t2 = , t3 = ; ; i<=n; i++) { t3 = t0+t1+t2; t0 = t1; t1 = t2; t2 = t3; } return t3; } };     参考 1. Leetcode_easy_1137. N-th Tribona…

Description e Tribonacci sequence Tn is defined as follows: T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2 for n >= 0. Given n, return the value of Tn. Example 1: Input: n = 4 Output: 4 Explanation: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4 Exampl…

这是小川的第409次更新,第441篇原创 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第260题(顺位题号是1137).Tribonacci(泰波那契)序列Tn定义如下: 对于n> = 0,T0 = 0,T1 = 1,T2 = 1,并且T(n+3) = T(n) + T(n+1) + T(n+2). 给定n,返回Tn的值. 例如: 输入:n = 4 输出:4 说明: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4 输入:n = 25 输出:138…

其实思路很简单,套用一下普通斐波那契数列的非递归做法即可,不过这个成绩我一定要纪念一下,哈哈哈哈哈 代码在这儿: class Solution: def tribonacci(self, n: int) -> int: a, b, c =0, 1, 1 if n is 0: return 0 if n is 1: return 1 if n is 2: return 1 for i in range(2, n): a, b ,c = b, c, a+b+c return c…

题目如下: The Tribonacci sequence Tn is defined as follows: T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2for n >= 0. Given n, return the value of Tn. Example 1: Input: n = 4 Output: 4 Explanation: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4 Example 2:…