Reverse Linked List,一道有趣的题目.给你一个链表,输出反向链表.因为我用的是JavaScript提交,所以链表的每个节点都是一个对象.例如1->2->3,就要得到3->2->1. 1.数组构造 一个很容易想到的方法是用数组保存新构造每个节点,然后反向构造链表,输出: var reverseList = function(head) { var ans = []; while (head) { var node = new ListNode(head.val);…
Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 反向链表,分别用递归和迭代方式实现. 递归Iteration: 新建一个node(value=任意值, next = None), 用一个变量 next 记录head.next,head.next指向新node.next,新 node.next…
题目: Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? 分析: 分别用迭代和递归来实现. 迭代就是新建一个…
题目描述: Reverse a singly linked list. 解题思路: 使用递归或者迭代的方法. 代码如下: 方法一:递归 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode reverseLi…