Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True  Example 2: Input: 5 / \ 3 6 / \ \ 2…

class Solution { public: bool findTarget(TreeNode* root, int k) { queue<TreeNode> Q; vector<int> V; if (root != NULL) { Q.push(*root); while (!Q.empty()) { TreeNode livenode = Q.front(); Q.pop(); V.push_back(livenode.val); if (livenode.left !=…

给定一个二叉搜索树和一个目标结果,如果 BST 中存在两个元素且它们的和等于给定的目标结果,则返回 true. struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } }; class Solution { public: TreeNode* node; bool findTarget(TreeNo…

题目 直接暴力 1 class Solution { 2 public: 3 vector<int>ans; 4 bool findTarget(TreeNode* root, int k) { 5 dfs(root); 6 for(int i = 0;i <ans.size();i++) 7 for(int j = i + 1;j <ans.size();j++){ 8 if(ans[i] +ans[j] == k) 9 return true; 10 } 11 return f…

653. 两数之和 IV - 输入 BST 653. Two Sum IV - Input is a BST 题目描述 给定一个二叉搜索树和一个目标结果,如果 BST 中存在两个元素且它们的和等于给定的目标结果,则返回 true. LeetCode653. Two Sum IV - Input is a BST简单 案例 1: 输入: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 输出: True 案例 2: 输入: 5 / \ 3 6 / \ \ 2 4 7 Target…