POJ1837http://poj.org/problem?id=1837 题目大意就是说有一个称上有C个挂钩,告诉你每个挂钩的位置,现在有G个重物,求是之平衡的方法数. 转化一下:DP[i][j]表示第i个物品挂上之后偏移量为j的方法数,所以最后结果就是DP[C][0].下标不能有负数,所以整体往右移动7500即可. #include <map> #include <set> #include <stack> #include <queue> #inclu…

Balance Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 13717   Accepted: 8616 Description Gigel has a strange "balance" and he wants to poise it. Actually, the device is different from any other ordinary balance. It orders two arms…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=5616 题目: Jam's balance Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1810    Accepted Submission(s): 754 Problem Description   Jim has a balance…

Description Gigel has a strange "balance" and he wants to poise it. Actually, the device is different from any other ordinary balance. It orders two arms of negligible weight and each arm's length is 15. Some hooks are attached to these arms and…

Balance  POJ - 1837 题目大意: 有一个天平,天平左右两边各有若干个钩子,总共有C个钩子,有G个钩码,求将钩码全部挂到钩子上使天平平衡的方法的总数. 其中可以把天枰看做一个以x轴0点作为平衡点的横轴 输入: 2 4 //C 钩子数 与 G钩码数 -2 3 //负数:左边的钩子距离天平中央的距离:正数:右边的钩子距离天平中央的距离c[k] 3 4 5 8 //G个重物的质量w[i] /* 首先定义一个平衡度j的概念:当平衡度j=0时,说明天枰达到平衡, j>0,说明天枰倾向右边(…

 POJ 1837 -- Balance 转载:優YoU   http://user.qzone.qq.com/289065406/blog/1299341345 提示:动态规划,01背包 初看此题第一个冲动就是穷举....不过再细想肯定行不通= =O(20^20)等着超时吧... 我也是看了前辈的意见才联想到01背包,用动态规划来解 题目大意: 有一个天平,天平左右两边各有若干个钩子,总共有C个钩子,有G个钩码,求将钩码全部挂到钩子上使天平平衡的方法的总数. 其中可以把天枰看做一个以x轴0点作…

C. Balance 题目链接 http://codeforces.com/contest/17/problem/C 题面 Nick likes strings very much, he likes to rotate them, sort them, rearrange characters within a string... Once he wrote a random string of characters a, b, c on a piece of paper and began…

题目大意: 有一个天平,天平左右两边各有若干个钩子,总共有C个钩子(每个钩子有相对于中心的距离,左负右正),有G个钩码,求将钩码全部挂到钩子上使天平平衡的方法的总数. 将每个砝码看作一组,组内各个物品的体积为每个挂钩与该砝码形成的力矩,背包总体积严格为0,这便是分组背包计数问题(特殊点:每一组必须出一个物品,而不是至多出一个物品).由于c++不允许负的数组下标,所以每次更新时,j要加上offsetJ. 实现分组背包计数问题时,可以用填表法(找以前节点求自己值)(DP1)或刷表法(找以后节点更新以…

The Balance Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5956    Accepted Submission(s): 2427 Problem Description Now you are asked to measure a dose of medicine with a balance and a number o…

原文链接 https://www.cnblogs.com/cly-none/p/ECFINAL2018J.html 题意:给出一个长度为\(n\)的字符串\(s\),要求给\(s\)的每个后缀\(s[i:]\)分配权值\(k_i\)(实数),满足\(0 \leq k_i \leq 1\),且\(\sum_i k_i = 1\).再此基础上,最大化 \[ \min_{i=1}^n \left( \sum_{j=1}^n k_j {\rm {lcp}} (s[i:],s[j:]) \right) \…