Problem Description Three wizards are doing a experiment. To avoid from bothering, a special magic is set around them. The magic forms a circle, which covers those three wizards, in other words, all of them are inside or on the border of the circle.…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 137 Accepted Submission(s): 94 Problem Description Three wizards are doing a experiment. To avoid from bothering, a spe…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 228 Accepted Submission(s): 163 Problem Description Three wizards are doing a experiment. To avoid from bothering, a special…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 452 Accepted Submission(s): 307 Problem Description Three wizards are doing a experiment. To avoid from bothering, a sp…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 24 Accepted Submission(s): 17 Problem Description Three wizards are doing a experiment. To avoid from bothering, a spec…
Description Three wizards are doing a experiment. To avoid from bothering, a special magic is set around them. The magic forms a circle, which covers those three wizards, in other words, all of them are inside or on the border of the circle. And due…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 152 Accepted Submission(s): 107 Problem Description Three wizards are doing a experiment. To avoid from bothering, a s…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 61 Accepted Submission(s): 39 Problem Description Three wizards are doing a experiment. To avoid from bothering, a spe…
HDU4716 A. A Computer Graphics Problem A题目描述 题意:输出手机剩余电量,保证给出的数是10的倍数. 题解:水题,按题意输出即可. 代码: #include <cstdio> #include <cstring> #include <algorithm> #define ll long long using namespace std; int main() { ,n,m; for (scanf("%d",&a…
先明确一些潜规则: 机器学习是个collection or set of models,一切实践性强的模型都会被归纳到这个领域,没有严格的定义,’有用‘可能就是唯一的共性. 机器学习大概分为三个领域: 一般的机器学习模型:没有掺杂太多统计概念,例如决策树,KNN聚类,感知机等. 统计机器学习模型:依赖统计理论,主要是贝叶斯统计,例如SVM,naive bayesian,贝叶斯线性回归,高斯过程等. 神经网络模型:可以简单的理解为感知机的扩展,因为扩展的太猛,单独成立门派咯. 如此定义,有助于菜鸡…
先明确一些潜规则: 机器学习是个collection or set of models,一切实践性强的模型都会被归纳到这个领域,没有严格的定义,’有用‘可能就是唯一的共性. 机器学习大概分为三个领域: 一般的机器学习模型:没有掺杂太多统计概念,例如决策树,KNN聚类,感知机等. 统计机器学习模型:依赖统计理论,主要是贝叶斯统计,例如SVM,naive bayesian,贝叶斯线性回归,高斯过程等. 神经网络模型:可以简单的理解为感知机的扩展,因为扩展的太猛,单独成立门派咯. 如此定义,有助于菜鸡…
http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1610 Accepted Submission(s): 630 Problem Description (From wikipedia) For bina…
hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup Herding Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2005 Accepted Submission(s): 563 Problem Description Little Joh…
朴素贝叶斯是一种很简单的分类方法,之所以称之为朴素,是因为它有着非常强的前提条件-其所有特征都是相互独立的,是一种典型的生成学习算法.所谓生成学习算法,是指由训练数据学习联合概率分布P(X,Y),然后求得后验概率P(X|Y).具体来说,利用训练数据学习P(X|Y)和p(Y)的估计,得到联合概率分布: 概率估计可以是极大似然估计,或者贝叶斯估计. 假设输入 X 为n维的向量集合,输出 Y 为类别,X 和 Y 都是随机变量.P(X,Y)是X和Y的联合概率分布,训练数据集为:…
Introduction the naive "scull" 首先.什么是scull? scull (Simple Character Utility for Loading Localities). scull is a char driver that acts on a memory area as though it were a device. 和第一个C程序Hello world一样.他什么都不能干,却能非常好的阐释怎么一步步进阶的去写驱动 blog的最后,我会给出这对于s…