Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Credits:Special thanks to @t…

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描述:Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路1:Moore voting algorith…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 思路 hashmap统计次数 摩尔投票法 Moore Voting 位运算统计位数 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/majority-element/ Total Accepted: 110538 Total Submissions: 268289 Difficulty: Easy 题目…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路.1 排序,选择第n/2个数,调用STL的sort,…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Solution 1: 使用map计数 class So…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it possibly have? Do you have a better hint? Suggest it! [题目分析]…

题目:Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. int majorityElement(vecto…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 求大于数组一半的元素,思想主要是对于大于数组一般的元素,…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 求主元素,这次的是大于sz/3就算是主元素,可以分为两轮查找,第一轮先查找元素数目较多的两个元素(可能不属于主元素),第二次再遍历来查找上面两个元素是否符合条件,代码如下: class Solution…

169. Majority Element 求超过数组个数一半的数 可以使用hash解决,时间复杂度为O(n),但空间复杂度也为O(n) class Solution { public: int majorityElement(vector<int>& nums) { unordered_map<int,int> count; int n=nums.size(); ;i<n;i++){ ) return nums[i]; } ; } }; 使用投票法,时间复杂度为O(…

169. Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路1:ha…

169. Majority Element /** * @param {number[]} nums * @return {number} */ var majorityElement = function(nums) { var hash = {}; var y=-1,z; //注意这里的方括号,利用变量访问对象属性时要用方括号 for(var i=0;i<=nums.length-1;i++){ if(hash[nums[i]]){ hash[nums[i]]++; }else{ hash[…

题目描述 给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素. 你可以假设数组是非空的,并且给定的数组总是存在众数. 示例 1: 输入: [3,2,3] 输出: 3 示例 2: 输入: [2,2,1,1,1,2,2] 输出: 2 思路 思路一: 利用哈希表的映射,储存数组中的数字以及它们出现的次数,当众数出现时,返回这个数字. 思路二: 因为众数是出现次数大于n/2的数字,所以排序之后中间的那个数字一定是众数.即nums[n/2]为众数.但是在计算比…

Question 169. Majority Element Solution 思路:构造一个map存储每个数字出现的次数,然后遍历map返回出现次数大于数组一半的数字. 还有一种思路是:对这个数组排序,次数超过n/2的元素必然在中间. Java实现: public int majorityElement(int[] nums) { Map<Integer, Integer> countMap = new HashMap<>(); for (int num : nums) { In…

这周刚开始讲了一点Divide-and-Conquer的算法,于是这周的作业就选择在LeetCode上找分治法相关的题目来做. 169.Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-e…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 hashmap统计次数 摩尔投票法 Moore Voting 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/majority-element-ii/description/ 题目描述 Given an integer array of size n, find all elements that ap…

169. Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 题目大意:…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 题目标签:Array 忘记说了,特地回来补充,今天看完<…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路: Find k different element…

1. 题目描述Description Link: https://leetcode.com/problems/majority-element/description/ Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-e…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Example 1: Input: [3,2,3] Ou…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 给定一个数组,求其中权制最大的元素,(该元素出现超过了一…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 分析: 遍历数组,每当发现一对儿不相同的element时…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 解题思路: 编程之美P130(寻找发帖水王)原题,如果删…

#Method 1import math class Solution(object):    def majorityElement(self, nums):        numsDic={}        for num in nums:            numsDic[num]=numsDic[nums]+1 if num in numsDic else 0            if numsDic[num]>len(nums)/2:                return…

一个数组里有一个数重复了n/2多次,找到 思路:既然这个数重复了一半以上的长度,那么排序后,必然占据了 a[n/2]这个位置. class Solution { public: int majorityElement(vector<int>& nums) { sort(nums.begin(),nums.end()); return nums[nums.size()/2]; } }; 线性解法:投票算法,多的票抵消了其余人的票,那么我的票一定还有剩的. int majority; in…

题目描述: Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 解题思路: 每找出两个不同的element,…

题目链接:majority-element /** * Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array.…

题目要求 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 题目分析及思路 给定一个长度为n的数组,找到m…