HDUOJ--1865 1string】的更多相关文章

题目链接:http://acm.hust.edu.cn/vjudge/contest/121397#problem/F http://acm.hdu.edu.cn/showproblem.php?pid=1865 Description You will be given a string which only contains ‘1’; You can merge two adjacent ‘1’ to be ‘2’, or leave the ‘1’ there. Surly, you ma…
http://acm.hdu.edu.cn/showproblem.php?pid=1455 http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=243 uva开头描述: 307 - Sticks Time limit: 3.000 seconds hduoj 开头描述: E - Sticks Time Limit:3000MS     Memo…
http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1610    Accepted Submission(s): 630 Problem Description (From wikipedia) For bina…
hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup Herding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2005    Accepted Submission(s): 563 Problem Description Little Joh…
最短路基础 这个题目hdu-oj 1874可以用来练习最短路的一些算法. Dijkstra 无优化版本 #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #define mt memset using namespace std; const int maxn = 210; const int inf = 1<<30; int N,M; int mp…
版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. HDUoj 5391 - Zball in Tina Town 在线提交: http://acm.hdu.edu.cn/showproblem.php?pid=5391 Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 262144/262144 K (Ja…
版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C++版 - HDUoj 2010 3阶的水仙花数 - 牛客网 时间限制:1秒 空间限制:32768K 热度指数:1005 在线提交(牛客网仅支持C++或Java): https://www.nowcoder.com/questionTerminal/dc943274e8254a9eb074298fb208470…
1sting Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2372    Accepted Submission(s): 947 Problem Description You will be given a string which only contains ‘1’; You can merge two adjacent ‘1’…
HDUOJ题目HTML的爬取 封装好的exe/app的GitHub地址:https://github.com/Rhythmicc/HDUHTML 按照系统选择即可. 其实没什么难度,先爬下来一个题目的html,然后正则匹配一波塞个标签上去就好了. 下图运行效果: 下面是爬取下的HTML运行效果: 源码: import re import requests from requests.exceptions import RequestException url = "http://acm.hdu.…
基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029.1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093.1094.1095.1096.1097.1098.1106.1108.1157.1163.1164.1170.1194.1196.1197.1201.1202.1205.1219.1234.1235.1236.1248.1…